Question:
a. Diffusion
b. Facilitated diffusion
c. Both
d. Neither
1. movement to area of lower concentration
2. movement across a membrane
3. steroid transport into cell
4. requires energy
5. movement assisted by proteins
6. glucose transport into cell
Answer:
The sorting is as follows
a. (1)
b. (5 and 6)
c. (1 and 2)
d. (4)
Explanation:
Diffusion is the movement of particles across a membrane from a high concentration region to one with a lower concentration of the diffusing substance
Here we have the correct sorting as follows
a. Diffusion
3. steroid transport into cell
b. Facilitated diffusion
5. movement assisted by proteins
6. glucose transport into cell
c. Both
1. movement to area of lower concentration
2. movement across a membrane
d. Neither
4. requires energy
Answer:
B. The reaction would shift to produce more O2 and SO2-
Explanation:
This is because the forward reaction is exothermic.
Answer:
3300.85 g
Explanation:
Given data:
Mass of ZnCl₂ produced = ?
Mass of H₂ produced = 49.8 g
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of moles of H₂:
Number of moles = mass/molar mass
Number of moles = 49.8 g/ 2.056 g/mol
Number of moles = 24.22 mol
Now we will compare the moles of H₂ with ZnCl₂ form balance chemical equation.
H₂ : ZnCl₂
1 : 1
24.22 : 24.22
Mass of ZnCl₂:
Mass = number of moles × molar mass
Mass = 24.22 × 136.286 g/mol
Mass = 3300.85 g
Answer:
A. 30cm³
Explanation:
Based on the chemical reaction:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
<em>1 mol of calcium carbonate reacts with 2 moles of HCl to produce 1 mol of CO₂</em>
<em />
To solve this question we must convert the mass of each reactant to moles. With the moles we can find limiting reactant and the moles of CO₂ produced. Using PV = nRT we can find the volume of the gas:
<em>Moles CaCO₃ -Molar mass: 100.09g/mol-</em>
1.00g * (1mol / 100.09g) = 9.991x10⁻³ moles
<em>Moles HCl:</em>
50cm³ = 0.0500dm³ * (0.05 mol / dm³) = 2.5x10⁻³ moles
For a complete reaction of 2.5x10⁻³ moles HCl there are necessaries:
2.5x10⁻³ moles HCl * (1mol CaCO₃ / 2mol HCl) = 1.25x10⁻³ moles CaCO₃. As there are 9.991x10⁻³ moles, HCl is limiting reactant.
The moles produced of CO₂ are:
2.5x10⁻³ moles HCl * (1mol CO₂ / 2mol HCl) = 1.25x10⁻³ moles CO₂
Using PV = nRT
<em>Where P is pressure = 1atm assuming STP</em>
<em>V volume in L</em>
<em>n moles = 1.25x10⁻³ moles CO₂</em>
<em>R gas constant = 0.082atmL/molK</em>
<em>T = 273.15K at STP</em>
<em />
V = nRT / P
1.25x10⁻³ moles * 0.082atmL/molK*273.15K / 1atm = V
0.028L = V
28cm³ = V
As 28cm³ ≈ 30cm³
Right option is:
<h3>A. 30cm³</h3>
