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arlik [135]
3 years ago
5

The base of an isosceles triangle is one and a half times the length of the other two sides. A smaller triangle has a perimeter

that is half the perimeter of the first. Write an expression for the perimeter of the smaller triangle and combine like terms. What is the simplified expression?
Mathematics
1 answer:
stira [4]3 years ago
5 0

Answer:

P = 1.5x.

Step-by-step explanation:

Let the length of each side of the first triangle be x, then

Perimeter of this triangle

= 2x + 1.5x

= 3.5x.

So perimeter of smaller triangle is:

P = 1/2 * 3.5x

P = 1,.5x.

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Answer:

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x=500

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What is the sum of the expressions (2/3x −7)+(1/3 x+5)?
Anit [1.1K]
The answer is

Final result :

x - 2
Step by step solution :

Step 1 :

1
Simplify —
3
Equation at the end of step 1 :

2 1
((—•x)-7)+((—•x)+5)
3 3
Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1 Adding a whole to a fraction

Rewrite the whole as a fraction using 3 as the denominator :

5 5 • 3
5 = — = —————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x + 5 • 3 x + 15
————————— = ——————
3 3
Equation at the end of step 2 :

2 (x + 15)
((— • x) - 7) + ————————
3 3
Step 3 :

2
Simplify —
3
Equation at the end of step 3 :

2 (x + 15)
((— • x) - 7) + ————————
3 3
Step 4 :

Rewriting the whole as an Equivalent Fraction :

4.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

7 7 • 3
7 = — = —————
1 3
Adding fractions that have a common denominator :

4.2 Adding up the two equivalent fractions

2x - (7 • 3) 2x - 21
———————————— = ———————
3 3
Equation at the end of step 4 :

(2x - 21) (x + 15)
————————— + ————————
3 3
Step 5 :

Adding fractions which have a common denominator :

5.1 Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(2x-21) + (x+15) 3x - 6
———————————————— = ——————
3 3
Step 6 :

Pulling out like terms :

6.1 Pull out like factors :

3x - 6 = 3 • (x - 2)

Final result :

x - 2

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