Answer:
Δy = 7.1 cm
Explanation:
The center of mass of a body is defined
= 1 /M ∑
i
Where M is the total mass of the body, m mass of each part and ‘y’ height
Let's apply this equation to our case
We locate the reference system on the shoulders
The height of the arms is at its midpoint
y = -75/2 = 37.5 cm
With arms down
= 1/70 (63 y₀ - 3.5 37.5 - 3.5 37.5)
= 1/70 (63 y)₀ - 7 37.5)
With arms up
’= 1/70 (63 y₀ + 3.5 y + 3.5 y)
’= 1/70 (63y₀ + 7 35.5)
let's subtract the two equations
’ - = 1/70 2 (7 35.5)
Δy = ’ - = 2 7 35.5 / 70
ΔY = 7.1 cm
Answer: 4.98 m/s
Explanation:
You solve these kinetic energy, potential energy problems by using the fact P.E.+ K.E. = a constant as long as friction is ignored.
PEi = 0 in this case
KEi = ½mVi² = PEf+KEf = mghf + ½mVf²
½1210*8.31² = 1210*9.8*2.26 + ½1210*Vf²
½1210*Vf² = ½1210*8.31² - 1210*9.8*2.26
Vf² = 8.31² - 2*9.8*2.26 = 4.98² so Vf = 4.98m/s
Hydrogen gas is harmless to your feet so since you don’t need protection against it that seems the best answer.
From the law of conservation of momentum
m1u1+ m2u2= m1v1+ m2v2
110*8+ 110*-10= 110*-10 + 110* v2
v2= 8 m/sec
Decrease the reactance is the correct answer i believe
Explanation:
