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Rainbow [258]
3 years ago
10

Four moles of hydrogen chloride (HCl) gas react with one mole of oxygen (O2) gas to produce two moles of chlorine gas (Cl2) and

two moles of water gas (H2O). Using this description of the reaction, write the corresponding chemical equation, showing the appropriate coefficients for each reactant and product. (Include states-of-matter under the given conditions in your answer.)
Chemistry
2 answers:
Marianna [84]3 years ago
7 0

Answer:

4HCl(g) + O₂(g) →  2Cl₂(g) + 2H₂O(g)

Explanation:

In order to find the equation we should state:

The reactants → Hydrogen chloride (HCl) and oxygen (O₂)

The products → Chlorine gas (Cl₂) and water gas (H₂O)

The balanced equation is:

4HCl + O₂  →  2Cl₂ + 2H₂O

It is a redox reaction, where the oxygen reduces to make water, and the chloride is oxidized to produce elemental chlorine.

ANEK [815]3 years ago
7 0

Answer:

4HCl(g) + O2(g) → 2Cl2(g) + 2H2O(g)

Explanation:

Step 1: Data given

Number of moles hydrogen chloride (HCl) = 4.0 moles

Number of moles oxygen gas (O2) = 1.0 moles

Number of moles chlorine gas (Cl2) produced = 2.0 moles

Number of moles of water gas (H20) = 2.0 moles

Step 2: The unbalanced equation

HCl(g) + O2(g) → Cl2(g) + H2O(g)

Step 3: Balancing the equation

HCl(g) + O2(g) → Cl2(g) + H2O(g)

On the left side we have 2x O (in O2), on the right side we have 1x O (in H2O).

To balance the amount of O on both sides, we have to multiply H2O on the right side by 2.

HCl(g) + O2(g) → Cl2(g) + 2H2O(g)

On the left side we have 1x H (in HCl), on the right side we have 4x H (in 2H2O). To balance the amount of H on both sides, we have to multiply HCl on the left side by 4.

4HCl(g) + O2(g) → Cl2(g) + 2H2O(g)

On the left side we have 4x Cl (in 4HCl), on the right side we have 2x Cl (in Cl2). To balance the amount of Cl on both sides,we have to multiply Cl2 by 2. Now the equation is balanced.

4HCl(g) + O2(g) → 2Cl2(g) + 2H2O(g)

This means for 4 moles Hcl we need 1 mol O2 to react to produce 2 moles Cl2 and 2 moles H2O

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The independent variable would be the variable in the research that is being manipulated by the researcher. In this case, it would be amount of food as it is what is being manipulated and changed in the research design. The dependent variable would be the variable that is being studied so, for this case, it would be the weight gain of the mice. The constants are the factors that might affect the dependent variable but is held constant or the same by the researcher throughout the experiment. These are the size of cage, amount of water, amount of sunlight, temperature and the exercise wheel.

5 0
3 years ago
Which of the following solutes has the greatest effect on the colligative properties for a given mass of pure water? Explain.
Strike441 [17]

Answer:

Option a.

0.01 mol of CaCl₂ will have the greatest effect on the colligative properties, because it has the biggest i

Explanation:

To determine which of the solute is going to have a greatest effect on colligative properties we have to consider the Van't Hoff factor (i)

These are the colligative properties:

ΔP = P° . Xm . i  →  Lowering vapor pressure

ΔT = Kb . m . i  → Boiling point elevation

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π = M . R . T  →  Osmotic pressure

Van't Hoff factor are the numbers of ions dissolved in the solution. For nonelectrolytes, the i values 1.

CaCl₂ and KNO₃ are two ionic solutes. They dissociate as this:

CaCl₂  → Ca²⁺ + 2Cl⁻

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KNO₃ → K⁺ + NO₃⁻

We have 1 mol of K⁺ and 1 mol of nitrate, so 2 moles of ions → i = 2

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8 0
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In the compound potassium nitrate (KNO3), the atoms within the nitrate ion are held together with bonding, and the potassium ion
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Ionic bonds form when one atom gives up one or more electrons to another atom. It is the complete transfer of valence electron(s) between oppositely charged atoms.  Ionic bond is formed between metal (electropositive element) and non-metal(electronegative element)

In nitrate ions the Nitrogen (N) and Oxygen (O) both are non-metals and it involves the sharing of electron pairs between N and O atoms, so the bonding in Nitrate (NO_{3}^{-}) ion is covalent bonding.

In potassium nitrate , Potassium (K) is a metal and Nitrate (NO_{3}^{-}) ion is non-metal and it involves the complete transfer of valence electron between oppositely charged atoms (K+) and (NO_{3}^{-}). So the bonding between Potassium and Nitrate is Ionic bonding.

NOTE : Bonding between Non-metals is Covalent bonding.

Bonding between Metal and Non-metals is Ionic bonding.



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Answer:

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Explanation:

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