1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kaheart [24]
2 years ago
8

Hydrogen peroxide with a concentration of 3.0 percent (3.0 g of H2O2 in 100 mL of solution) is sold in drugstores for use as an

antiseptic. For a 10.0-mL 3.0 percent H2O2 solution, calculate (a) the oxygen gas produced (in liters) at STP when the compound undergoes complete decomposition and (b) the ratio of the volume of O2 collected to the initial volume of the H2O2 solution.
Chemistry
1 answer:
vlabodo [156]2 years ago
4 0

Answer:

a) 0.099 L

b) 9.9

Explanation:

Now, given the equation for the decomposition of H2O2;

2H2O2(l) ------> 2H2O(l) + O2(g)

Mass of H2O2;

percent w/v concentration = mass/volume * 100

volume = 10.0-mL

percent w/v concentration = 3.0 percent

mass of  H2O2 = x

3 = x/ 10 * 100

30 = 100x

x = 30/100

x = 0.3 g of H2O2

Number of moles in  0.3 g of H2O2 = mass/ molar mass

Molar mass of H2O2 = 34.0147 g/mol

Number of moles in  0.3 g of H2O2 = 0.3g/34.0147 g/mol

= 0.0088 moles

From the reaction equation;

2 moles of H2O2 yields 1 mole of oxygen

0.0088 moles of H2O2 = 0.0088 * 1/2  = 0.0044 moles of oxygen

If 1 mole of oxygen occupies 22.4 L

0.0044 moles of oxygen occupies 0.0044 *  22.4/1

= 0.099 L

b) initial volume of the H2O2 solution = 10 * 10-3 L

Hence, ratio of the volume of O2 collected to the initial volume of the H2O2 solution = 0.099 L/10 * 10-3 L = 9.9

You might be interested in
Which properties of a substance could change during a<br> PHYSICAL change?
olga2289 [7]
It’s appearance
It’s physical form
What it feels like
How hot it gets
If it melts
Shape
Color
4 0
2 years ago
at what temperature will you find more potassium nitrate(kno3) in 100 g of H2O . In other words at which temperature will you ha
Oksana_A [137]
The answer to this question would be: <span>85c 
</span>Solubility is influenced by the temperature of the molecule. Higher temperature will result in a higher solubility. That is why brewing using hot water will be easier than using cold water. Higher temperature also means higher reaction rate.
4 0
3 years ago
How many moles of helium are needed to fill a balloon to a volume of 6.3 L at 28 °C and 320
Ray Of Light [21]

Answer:

.11 mol

Explanation:

Convert mmHg to atms by dividing by 760. Then multiply 6.3 by the atms and divide by .08206*(273+28) to get mol

5 0
2 years ago
Read 2 more answers
He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o
Xelga [282]

Answer : The activation energy of the reaction is, 17.285\times 10^4kJ/mole

Solution :  

The relation between the rate constant the activation energy is,  

\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = initial rate constant = 4.55\times 10^{-5}L/mole\text{ s}

K_2 = final rate constant = 8.75\times 10^{-3}L/mole\text{ s}

T_1 = initial temperature = 195^oC=273+195=468K

T_2 = final temperature = 258^oC=273+258=531K

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]

Ea=17.285\times 10^4kJ/mole

Therefore, the activation energy of the reaction is, 17.285\times 10^4kJ/mole

8 0
3 years ago
Read 2 more answers
How many pounds of coal would you have to burn to generate enough heat to boil a 15 l kettle?
rjkz [21]
Note that
The heating value of standard coal is about 30,080 kJ/kg
1 L of water has a mass of 1.0 kg

The mass of 15 L of water = 15 kg.
The latent heat of vaporization of water is about 2260 kJ/kg,
 The energy required to boil 15 L of water is
(2260 kJ/kg)*(15 kg) = 33900 kJ

The mass of coal required to provide this energy is
(33900 kJ)/(30080 kJ/kg) = 1.127 kg

Because 1 kg = 2.205 lb, the mass of coal required is
(1.127 kg)*(2.205 lb/kg) = 2.485 lb

Answer: 2.49 lb (nearest hundredth)

7 0
2 years ago
Other questions:
  • How do the conditions for hurricane differ from the conditions for tornado?
    6·1 answer
  • Calculate the mass (in g) of 2.1 x 1024 atoms of W.
    10·1 answer
  • An electrochemical cell is constructed using two half-cells: Al(s) in Al(NO2)3(aq) and Cu(s) in Cu(NO3)2(aq). The two half cells
    6·1 answer
  • Explain why oxygen is a fairly reactive element while neon is not
    5·1 answer
  • Write a balanced chemical equation for the following: magnesium metal is burned in oxygen to produce magnesium oxide.
    5·1 answer
  • 0.30 kg cart moves on an air track at 1.2 m/s.It collides with and sticks to another cart of mass 500 g,which was stationary bef
    14·1 answer
  • Explain<br><br><br>diffusion in solids <br><br><br><br><br><br>have a great day ​
    15·1 answer
  • In dimensional analysis you should always have the same units adjacent to each other (top left to bottom right)
    9·1 answer
  • Draw the curved arrows showing a proton transfer reaction, and draw the products of that proton transfer. Do not include the Li
    10·1 answer
  • How many atoms are in this compound?<br> C4H10N5O5
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!