Calculate the Kelvin temperatures of the water and record your answers in the data table.

Consider an exceptionally weak acid, HA, with a Ka = 1x10 -20 . You make a 0.1M solution of the salt Na

Vedmedyk [2.9K]

Answer:

$pH=13$

Explanation:

Hello,

In this case, given the acid, we can suppose a simple dissociation as:

$HA\rightleftharpoons H^+ + A^-$

Which occurs in aqueous phase, therefore, the law of mass action is written by:

$Ka=\frac{[H^+][A^-]}{[HA]}$

That in terms of the change $x$ due to the reaction's extent we can write:

$1x10^{-20}=\frac{x*x}{0.1M-x}$

But we prefer to compute the Kb due to its exceptional weakness:

$Kb=\frac{Kw}{Ka}=\frac{1x10^{-14}}{1x10^{-20}} =1x10^{-6}$

Next, the acid dissociation in the presence of the base we have:

$Kb=\frac{[OH^-][HA]}{[A^-]}=1x10^{6}=\frac{x*x}{0.1-x}$

Whose solution is $x=0.0999M$ which equals the concentration of hydroxyl in the solution, thus we compute the pOH:

$pOH=-log([OH^-])=-log(0.0999)=1$

Finally, since the maximum scale is 14, we can compute the pH by knowing the pOH:

$pH+pOH=14\\\\pH=14-pOH=14-1\\\\pH=13$

Regards.

5 0

3 years ago

Read 2 more answers

Enter an equation to show how h2po3− can act as a base with hs− acting as an acid. Express your answer as a chemical equation. I

vladimir2022 [97]

The acid - base equation between H2PO3^- and HS^- is H2PO3^- + HS^- ⇄S^- + H3PO3.

An acid is a substance that can donate hydrogen ions while a base is a substance that can accept hydrogen ion. This is the acid base definition according to Brownstead - Lowry.

To show the acid - base relationship between H2PO3^- and HS^-, we have the equation;

H2PO3^- + HS^- ⇄S^- + H3PO3

Learn more about acids and bases: brainly.com/question/10282816

4 0

2 years ago

A group of students created a model showing a type of matter which of the following discribes what is shows by the model?

Lady_Fox [76]

Answer:

liquid

Explanation:

6 0

3 years ago

What is the chemical formula for 8.6 mol of sulfur and 3.42 mol of phosphorus

adell [148]

The chemical formula for the compound containing 8.6 mol of sulfur and 3.42 mol of phosphorus is P₂S₅

<h3>How do I determine the formula of the compound?</h3>

From the question given above, the following data were obatined:

Sulphur (S) = 8.6 moles
Phosphorus (P) = 3.42 mole
Chemical formula =?

The chemical formula of the compound can be obtained as follow:

Divide by their molar mass

S = 8.6 / 32 = 0.26875

P = 3.42 / 31 = 0.11032

Divide by the smallest

S = 0.26875 / 0.11032 = 2.44

P = 0.11032 / 0.11032 = 1

Multiply by 2 to express in whole number

S = 2.44 × 2 = 5

P = 1 × 2 = 2

Thus, the chemical formula is P₂S₅

Learn more about empirical formula:

brainly.com/question/9459553

#SPJ1

5 0

1 year ago

The half-reaction occurring at the cathode in the balanced reaction shown below is __________?2Ag(s) + 1/2 O2(g) + 2H+(aq) → 2Ag

Shtirlitz [24]

Answer:

Correct choice are C and D (they are both, the same).

Explanation:

Cathode is the positive(+) electrode where a reduction occurs.

Reduction is the chemical reaction where the oxidation state is reduced.

2Ag(s) + 1/2 O2(g) + 2H+(aq) → 2Ag+(aq) + H2O (l)

A. 2H2O (l) → O2 (g) + 4H+ (aq) + 4e-

B. 2Ag (s) → 2Ag+ (aq) + 2e-

C. 1/2 O2 (g) + 2H+ (aq) + 2e- → H2O (l)

D. 1/2 O2 (g) + 2H+ (aq) + 2e- → H2O (l)

C or D, are ok. They are the same equation.

Oxygen from ground state reduce the oxidation state from 0 to -2

3 0

3 years ago