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devlian [24]
3 years ago
11

What is 4-5 as a percentage

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
6 0
80 percent...... Ratios are the same as fractions so its just like 4/5
Dahasolnce [82]3 years ago
6 0
\frac{4}{5} × 100

80%
 
Or change the fraction to decimal
\frac{4}{5} = 0.8

0.8 × 100
80%
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Ryobi Limited sold a set of saws to Ace Hardware. The list price was $3,800. Ryobi offered a chain discount of 8/3/1. What's the
laila [671]

Answer:  Option 'B' is correct.

Our net price will be $3357.21.

Explanation:

Since we have given that

The list price of set of saws = $3800

There are 3 successive discounts :

8%,3%,1%

So, if we apply first for 8% discount our new price becomes,

3800\times \frac{100-8}{100}=3800\times 0.92=\$3496

Now, if we apply 3% on our deducted price , our new price becomes ,

3496\times \frac{100-3}{100}=3496\times 0.97=\$3391.12

Now, we'll apply for 1% on our new deducted price , our net price becomes,

3391.12\times \frac{100-1}{100}=3391.12\times 0.99=\$3357.21

Hence, our net price will be $3357.21.

Therefore, Option 'B' is correct.


6 0
3 years ago
On a map the distance between St Petersburg, Fa, and Bladensburg. Md. Is shown below. If the actual
Alex73 [517]

Answer:

  1 inch = 82 miles

Step-by-step explanation:

You can divide each of the terms of this ratio by 14 to get the ratio for 1 inch:

  14 in : 1148 mi

  = (14 in)/14 : (1148 mi)/14

  = 1 in : 82 mi

8 0
3 years ago
AABC is a translation of AABC. What is the length of AC'?
Zinaida [17]
B.) 6?....
This seems too easy for it to be correct but I think it is B.
8 0
2 years ago
Read 2 more answers
5
AveGali [126]

Answer:

Total time taken by walking, running and cycling = 22 minutes.

Step-by-step explanation:

Let the speed of walking = x

As given,

The distance of walking = 1

Now,

As Time = \frac{Distance }{Speed}

⇒ Time traveled by walking = \frac{1}{x}

Now,

Given that - He runs twice as fast as he walks

⇒Speed of running = 2x

Also given distance traveled by running = 1

Time traveled by running = \frac{1}{2x}

Now,

Given that - he cycles one and a half times as  fast as he runs.

⇒Speed of cycling =  \frac{3}{2} (2x) = 3x

Also given distance traveled by cycling = 1

Time traveled by cycling = \frac{1}{3x}

Now,

Total time traveled = Time traveled by walking + running + cycling

                                = \frac{1}{x} +  \frac{1}{2x} + \frac{1}{3x}

                                = \frac{6+3+2}{6x} = \frac{11}{6x}

If he cycled the three mile , then total time taken = \frac{1}{3x} + \frac{1}{3x} + \frac{1}{3x} = x

Given,

He takes ten minutes longer than he would do if he cycled the three miles

⇒x + 10 = \frac{11}{6} x

⇒x - \frac{11}{6} x = -10

⇒-\frac{5}{6}x = -10

⇒x = \frac{60}{5} = 12

⇒x = 12

∴ we get

Total time traveled by walking + running + cycling = \frac{11}{6} x = \frac{11}{6} (12) = 11 (2) = 22 min

7 0
2 years ago
**URGENT PLEASE HELP ME TONIGHT >.<
Katena32 [7]
The rate of change for the graph would be the last option, 35. If you follow rise over run, you end up with a rise of 35 and a run of 1, or 35/1 which simplifies to 35.
5 0
3 years ago
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