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raketka [301]
3 years ago
14

Kilos pa iskapi halimbawa​

Physics
2 answers:
Firlakuza [10]3 years ago
7 0
Answer:

Step by step explanation:
kvv77 [185]3 years ago
7 0

Answer:

fb mb db gf adv ng dc n db ng d

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The continuity equation shows that the ratio of fluid velocities within different openings is inversely proportional to the cros
Stolb23 [73]

Answer:

A typical example of where the continuity equation can be applied, is in finding the cross sectional area of a laminar falling stream of water from a pipe at an elevation, at the point where it hits the ground.

The speed of the water through the discharge opening of the pipe can be measured with a flow-meter, and the cross sectional opening of the pipe is known.

As the water leaves the pipe, and falls towards the ground, the water stream is accelerated under gravity, and the speed of the water stream increase. The increase in the speed of the water stream causes the cross sectional area to decrease in obedience of the continuity law and equation. If the speed of can be measured, then the area of the water stream just before the water touches the ground  can be calculated from the continuity equation.

If the speed of the water stream can not be measured, then it can be calculated using Newton' equation of motion

v^{2} = u^{2} + 2gz

v = \sqrt{u^{2} + 2gz}

where

v = the velocity of the water stream at the point where it hits the ground

u = the velocity of the water at the pipe discharge (measured with a flow meter in the pipe)

g = acceleration due to gravity

z = the elevation of the pipe above the ground.

After calculating the speed of the water stream at the point where it hits the ground, the cross sectional area of the the stream can be calculated from the continuity equation.

uA = va

where

u and v are the velocities of the water stream at the pipe discharge and at the ground respectively.

A = the cross sectional area of the pipe

a = the area of the water stream before it hits the ground.

the equation is simplified as

a = \frac{uA}{v}

7 0
4 years ago
A clarinetist, setting out for a performance, grabs his 3.230 kg3.230 kg clarinet case (including the clarinet) from the top of
SpyIntel [72]

Answer:

- 0.5 m/s²

Explanation:

m = mass of the clarinet case = 3.230 kg

W = weight of the clarinet case in downward direction

a = vertical acceleration of the case

Weight of the clarinet case is given as

W = mg

W = 3.230 x 9.8

W = 31.654 N

F = Upward force applied = 30.10 N

Force equation for the motion of the case is given as

F - W = ma

30.10 - 31.654 = 3.230 a

a = - 0.5 m/s²

8 0
3 years ago
How do astronomers think the universe was created?
spin [16.1K]
<span>Most astronomers think that the Universe was formed during an event called the Big Bang - a giant explosion which occurred between 10 and 20 billion years ago. During the Big Bang, all of the space, time, matter, and energy in the Universe was created. This giant explosion hurled matter in all directions and caused space itself to expand. As the Universe cooled, the material in it combined to form galaxies, stars, and planets.</span>
5 0
3 years ago
Read 2 more answers
4. Suppose the observed motion of a moving airplane, illustrated by a distance vs. time graph, is nearly a straight line with ze
jekas [21]
It shows that the airplane covers equal distance in equal time interval, that's it has a straight line from the origin.

The plane is moving at uniform speed.
7 0
3 years ago
A series RC circuit contains a 1,000 ohm resistor and a 0.025 microfarad capacitor. What is the time constant of this circuit?
stiks02 [169]

The RC time constant, also called tau, the time constant (in seconds) of an RC circuit, is equal to the product of the circuit resistance (in ohms) and the circuit capacitance (in farads), i.e.

\tau = RC

Here,

R = Resistance

C = Capacitance

Replacing we have that

\tau = (1000)(0.025*10^{6})

\tau = 25*10^{-6}

\tau = 25\mu s

Therefore the time constant of this circuit is \tau = 25\mu s

5 0
3 years ago
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