Answer:
Option D is correct: 170 µW/m²
Explanation:
Given that,
Frequency f = 800kHz
Distance d = 2.7km = 2700m
Electric field Eo = 0.36V/m
Intensity of radio signal
The intensity of radial signal is given as
I = c•εo•Eo²/2
Where c is speed of light
c = 3×10^8m/s
εo = 8.85 × 10^-12 C²/Nm²
I = 3×10^8 × 8.85×10^-12 × 0.36²/2
I = 1.72 × 10^-4W/m²
I = 172 × 10^-6 W/m²
I = 172 µW/m²
Then, the intensity of the radio wave at that point is approximately 170 µW/m²
I think the answer is A
.
im not the best with physics but i think its right
Answer:
6.93m
Explanation:
Using the method of SOH CAH TOA
The base of the tree is 12m which is the adjacent side of the triangle to be generated, the height of the tree will be facing the angle of elevation and it is the opposite side.
Using the formula tan(theta) = Opposite/Adjacent
Given theta = 30°
Adjacent is 12m which is the distance the tree is making with the shadow on the ground
Opposite side will be the height of the tree.
Tan(theta) = height/12
Tan30° = height/12
Height = 12tan30°
Height = 6.93m
Therefore the height of the tree is 6.93m
Therefore electric potential is V = 15000V.
What is electric potential?
The amount of labor required to convey a unit of electric charge from a reference point to a given place in an electric field is known as the electric potential (also known as the electric field potential, potential drop, or the electrostatic potential).
length of sparks d = 5 mm = 5 x 10^-2 m
(a) It is possible to find average values for the skin's surface and the electric field in dry air from outside sources. Electric field and spark length can be used to determine electric potential.
V = E.d
V = 15000V
To learn more about electric potential click on the link below:
brainly.com/question/23980243
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