Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .
Answer:
56327040000 metres
Explanation:
1 mile =
1609.344 metres
35000000 miles = x meters
we represent x by the number of meters which the requested miles maps to
we cross multiply, so 1609.344×35000000 = 1 × x
x =56327040000 metres
Answer:
Explanation:
charge, q = 10 C
time, t = 2 micro second
Current, i = q / t
i = 10 / (2 x 10^-6) = 5 x 10^6 A
(a)
distance, d = 1 m
the formula for the magnetic field is given by
B = 1 Tesla
Now the distance is d' = 1 km = 1000 m
B' = 0.001 Tesla
(b) The magnetic field of earth is Bo = 3 x 10^-5 tesla
B / Bo = 3.3 x 10^4
B'/Bo = 33.3
