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artcher [175]
3 years ago
10

Answer these please.

Physics
1 answer:
PolarNik [594]3 years ago
5 0

Explanation:

hope this helps you

..........

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You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30 degre
katen-ka-za [31]
To calculate the velocity of the sound wave, we use this formula:
V = 331 + [0.6*T], 
Where V is the velocity and T represents temperature.
When the temperature is 36 degree Celsius, we have 
V = 331 + [0.6 * 36]
V = 331 + 21.6 = 352.6 
Therefore, V = 352.6 m/s.
7 0
3 years ago
Read 2 more answers
An automatic dryer spins wet clothes at an angular speed of 5.2 rad/s. Starting from rest, the dryer reaches its operating speed
Dvinal [7]
<h2>Time taken by dryer to come up to speed is 1.625 seconds.</h2>

Explanation:

We have equation of motion v = u + at

     Initial velocity, u =  0 rad/s

     Final velocity, v = 5.2 rad/s    

     Time, t = ?

     Acceleration, a = 3.2 rad/s²

     Substituting

                      v = u + at  

                      5.2 = 0 + 3.2 x t

                      t = 1.625 s

Time taken by dryer to come up to speed is 1.625 seconds.

6 0
3 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
choli [55]

Answer:

They can be seen from a distance of 4.372 kilometers.

Explanation:

Using the Reyligh creterion for diffraction through a circular aperture we have

\frac{x}{D}=\frac{1.22\lambda }{d}

where symbol's have their usual meaning

thus applying values we get

D=\frac{dx}{1.22\lambda }

\therefore D=\frac{0.633\times 4.61\times 10^{-3}}{1.22\times 547\times 10^{-9}}\\\\D=4372.77m\\=4.372km

5 0
3 years ago
In a circus act, a 70 kg clown is shot from a cannon with an initial velocity of 17 m/s at some unknown angle above the horizont
EleoNora [17]

Answer:

K_{2}=7302.4J

Explanation:

Given the initial velocity of the clown, his mass and final height we can calculate the final kinetic energy using the <em><u>conservation of total mechanical energy</u></em>

K_{1}+U_{1}=K_{2}+U_{2}

K_{2}=K_{1}+U_{1}-U_{2}

K_{2}=\frac{1}{2}mv_{1}^{2}+mgh_{1}-mgh_{2}

Since h_{1}=0

K_{2}=\frac{1}{2}mv_{1}^{2}-mgh_{2}

K_{2}=\frac{1}{2}(70kg)(17m/s)^2-(70kg)(9.8m/s^2)(4.1m)=7302.4J

K_{2}=7302.4J

7 0
3 years ago
Please help me, this school work is not the easiest for me.
lidiya [134]

Answer:

A = mm2

M = km2

F = mg

Explanation:

7 0
3 years ago
Read 2 more answers
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