Answer:
acceleration = 1.79 m/s^2
Tension = 6817 N
Explanation:
First let's find Elizabeth's weight:
Her weight is greater than the normal force (N = 450 N), so the elevator is going downwards.
The acceleration of Elizabeth is given by:
Where P is the weight of Elisabeth, N is her normal force, m is her mass and a is the acceleration. Then, we have that:
The tension in the cable is given by:
In this case, we use the total mass, so we have:
Explanation:
using the first eqn for motion
Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is
The value for static friction is
Explanation:
From the question we are told that
The mass of the clock is
The first horizontal force is
The second horizontal force is
Generally the static frictional force is equal to the first horizontal force
So
=>
=>
Generally the kinetic frictional force is equal to the second horizontal force
So
To solve this problem we will apply the concepts of equilibrium and Newton's second law.
According to the description given, it is under constant ascending acceleration, and the balance of the forces corresponding to the tension of the rope and the weight of the elevator must be equal to said acceleration. So
Here,
T = Tension
m = Mass
g = Gravitational Acceleration
a = Acceleration (upward)
Rearranging to find T,
Therefore the tension force in the cable is 10290.15N
