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Korvikt [17]
3 years ago
5

Please answer this question only if you know the answer! 30 points and brainliest!

Chemistry
2 answers:
liq [111]3 years ago
5 0

A. i think it’s  the  correct answer

telo118 [61]3 years ago
5 0

A. The circuit has insufficient power supplied by the battery

Was their meant to be a diagram?

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I need help pls Where does it belong to?​
Daniel [21]
The answer is B. Fungi,Protists
6 0
2 years ago
Calculate the decrease in temperarure when 2.00 L at 20.0 degrees celsius is compressed to 1.00 L.
Serga [27]
I suspect that the pressure of this change is constant therefore

The equation is used from the combined gas law. (When pressure is constant both P's will cancel out P/P = 1)
V/T = V/T
Initial   Change

Initially we have 2L at 20 degress what temperature will be at 1L.

2/20 = 1/T
0.1 = 1/T
0.1T = 1
T = 1/0.1
T = 10 degress celsius.

Hope this helps if you won't be able to understand what is the combined gas law just tell me :).
3 0
3 years ago
What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?
Marina86 [1]

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

6 0
3 years ago
What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
statuscvo [17]

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

M = Moles / Liter

.3151 L  x <u>0.5 mol EDTA</u>  x  <u>374 g EDTA</u>  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA

4 0
2 years ago
in the laboratory a student dilute 13.3 ml of a 10.8 m hcl solution to a total of 300.0 ml what is the concentration of the dilu
krek1111 [17]

<u>Answer:</u> The concentration of the diluted solution is 0.4788M

<u>Explanation:</u>

To calculate the concentration of the diluted solution, we use the following equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of HCl solution

M_2\text{ and }V_2 are the molarity and volume of the diluted HCl solution.

We are given:

M_1=10.8M\\V_1=13.3mL\\M_2=?M\\V_2=300mL

Putting values in above equation, we get:

10.8\times 13.3=M_2\times 300\\\\M_1=0.4788M

Hence, the concentration of the diluted solution is 0.4788M

6 0
3 years ago
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