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Vera_Pavlovna [14]
3 years ago
14

Select the true statement concerning voltaic and electrolytic cells. Select one: a. Voltaic cells involve oxidation-reduction re

actions while electrolytic cells involve decomposition reactions. b. Voltaic cells require applied electrical current while electrolytic cells do not. . c. all electrochemical cells, voltaic and electrolytic, must have spontaneous reactions. d. Electrical current drives nonspontaneous reactions in electrolytic cells.
Chemistry
2 answers:
kaheart [24]3 years ago
7 0

Answer:

electrolytic cells generate electricity through a non-spontaneous reaction while voltaic cells absorb electricity to drive a spontaneous reaction.

Explanation:

Answer via Educere/ Founder's Education

Volgvan3 years ago
4 0

Answer:

Electrical current drives nonspontaneous reactions in electrolytic cells.

Explanation:

Electrochemical cells are cells that produce electrical energy from chemical energy.

There are two types of electrochemical cells; voltaic cells and electrolytic cells.

A voltaic cell is an electrochemical cell in which electrical energy is produced from spontaneous chemical process while an electrolytic cell is an electrochemical cell where electrical energy is produced from nonspontaneous chemical processes. Current is needed to drive these nonspontaneous chemical processes in an electrolytic cell.

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When copper ii chloride reacts with sodium nitrate copper ii nitrate and sodium chloride are formed?
Nesterboy [21]
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2 years ago
Select all the correct answers.
Brut [27]

Hi!


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1. An experiment may have had errors that the scientist did not recognize. <u>(unintentional) </u>

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2 years ago
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4 0
2 years ago
What is the mass percent of sucrose (C12H22O11, Mm = 342 g/mol) in a 0.329-m sucrose solution?
Hitman42 [59]

Answer:

\% m/m=10.1\%

Explanation:

Hello,

In this case given the molal solution of sucrose, we can assume there are 0.329 moles of sucrose in 1 kg of solvent, thus, computing both the mass of sucrose and solvent in grams, we obtain:

m_{sucrose}=0.329mol*\frac{342g}{1mol}=112.5g

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In such a way, we proceed to the calculation of the mass percent as follows:

\% m/m=\frac{112.5g}{112.5g+1000g}*100\%\\ \\\% m/m=10.1\%

Regards.

8 0
3 years ago
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