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djyliett [7]
2 years ago
13

If 40.5 J of heat is added to a 15.4 g sample of silver, what will the change in temperature be? (Specific heat of silver is 0.2

35 J/g °C
Please hurry it’s due in 10 min :/
Chemistry
1 answer:
crimeas [40]2 years ago
4 0

Answer:

623.7

Explanation:

40.5*15.4=623.7

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Does Monocercomonoides still meet the definition of a eukaryote? Why or why not?
KengaRu [80]

Answer:

Yes

Explanation:

They are a unique type of eukaryote because they lack an important organelle: mitochondria. Mitochondria are essential for producing cellular energy in most eukaryotic cells. However, due to its habitat, it is able to acquire energy from a process called  sulfur mobilization.

They are significant because they challenge the idea that eukaryotes need mitochondria to be classified as eukaryotic. However, they have other membrane-bound organelles such as a nucleus and Golgi apparatus, meaning they remain eukaryotic.

Research suggest they lost their mitochondria over time, rather than never having had them throughout their ancestry.

Because of all these reasons, they still meet the definition of a eukaryote.

6 0
3 years ago
Identify how many of the original parent nuclei remain after three half-lives
Nutka1998 [239]

Answer:

yes

Explanation:

i did the test

3 0
3 years ago
For the following aqueous reaction, complete and balance the molecular equation and write a net iconic equatio, making sure to i
pav-90 [236]

Answer:

Balance molecular equation:

K2CO3(aq) + Sr(NO3)2(aq) → SrCO3(s) + 2KNO3(aq)

Net ionic equation:

CO3∧-2(aq) + Sr∧+2(aq) → SrCO3(s)

Explanation:

Potassium carbonate = K2CO3

Strontium nitrate = Sr(NO3)2

Chemical equation:

K2CO3 + Sr(NO3)2 → SrCO3 + KNO3

Balance chemical equation with physical states:

K2CO3(aq) + Sr(NO3)2(aq) → SrCO3(s) + 2KNO3(aq)

Ionic equation:

2K+(aq) + CO3∧-2(aq) + Sr∧+2(aq) + 2NO∧-3(aq) → SrCO3(s) + 2K+(aq) + 2NO∧-3(aq)

Net ionic equation:

CO3∧-2(aq) + Sr∧+2(aq) → SrCO3(s)

2K+ and 2NO∧-3 ions are spectator ions that's way these are not written in net ionic equation.

Spectator ions:

These are the ions that are present same on both side of chemical reaction and does not effect the equilibrium.

6 0
3 years ago
Which pair could be spectator ions?<br> (PLEASE HELP!)
Romashka [77]
I think the answer is yellow. Sorry if I got it wrong
4 0
3 years ago
What do you notice about the distance between the terrestrial planets compared with the spacing between the gas giants
LekaFEV [45]

Answer:

The spacing between the terrestrial planets is less than that between the gas planets.

Explanation:

Since the terrestrial planets which are Mercury, Venus, Earth and Mars have a distance of 0.4 AU, 0.7 A.U, 1.0 AU and 1.5 A.U respectively from while the gas planets which are Jupiter, Saturn, Uranus and Neptune have a distance of 5.2 AU, 9.6 AU, 19.6 AU and 30 AU respectively from the sun, we can see that the spacing between the terrestrial planets is much smaller than the spacing between the gas planets.

For example, the spacing between Mercury and Venus is 0.7 AU - 0.4 AU = 0.3 AU while that between Earth and Venus is 1.0 AU - 0.7 AU = 0.3 AU.

Also, the spacing between Earth and Mars is 1.5 AU - 1.0 AU = 0.5 AU.

Also too, the spacing between the gas planets is shown below  the spacing between Jupiter and Saturn is 9.6 AU - 5.2 AU = 4.4 AU while that between Uranus and Saturn is 19.6 AU - 9.6 AU = 10.0 AU.

Also, the spacing between Neptune and Uranus is 30 AU - 19.6 AU = 10.4 AU.

<u>Thus, we can see that the spacing between the terrestrial planets is less than that between the gas planets.</u>

Note that AU means astronomical unit and 1 AU is the distance between the Earth and the Sun. 1 AU = 1.50 × 10⁸ km

8 0
2 years ago
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