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torisob [31]
3 years ago
15

Chemicals A and B react according to the equation A + B → C. How will the concentrations of each component of the reaction chang

e over time?
The concentrations of A and C will increase, while B will decrease.

The concentrations of A and B will decrease, while C will increase.

The concentrations of A, B, and C will decrease.

The concentrations of A, B, and C will increase.
Chemistry
2 answers:
Firlakuza [10]3 years ago
7 0
The concentration of a and b will decrease while c will increase provided all other physical quantities are kept constant in the reaction
Irina18 [472]3 years ago
3 0

Answer:

The correct answer is ;The concentrations of A and B will decrease, while C will increase.

Explanation:

A + B → C

In the given reaction reactant A and B reacts with each other to form product C. As the reaction proceeds the concentration of A and B starts decreasing and concentration of product C increases.

In the end of the reaction concentration of C becomes greater than that of the  A and B concentration

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Name two methods that can be used to break down compounds into simpler substance
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Water which is used to break the bonds of molecules and split molecules is used from hydrolysis. Hydrolysis is made of three types which include;
1. salt hydrolysis.
2. acid hydrolysis.
3. Base hydrolysis.
 Photolysis is well known to use energy from light to split the molecule and the same energy is referred to as photons which are used to break builds of molecules.</span>
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Describe how hydrogen and oxygen form water
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Answer:

The  hydrogen molecules combine with the oxygen molecules, 2 hydrogen molecules, and 1 oxygen molecules is the amount needed to make one water atom or molecule, whatever you want to call it.

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Hydrogen sulfide decomposes according to the following reaction: 2H2S(g) ⇋ 2H2(g) + S2(g) Kc=9.30x10-8 at 700.°C.If 0.45 mol of
Natalija [7]

Answer:

[H₂] = 1.61x10⁻³ M

Explanation:

2H₂S(g) ⇋ 2H₂(g) + S₂(g)

Kc = 9.30x10⁻⁸ = \frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}

First we <u>calculate the initial concentration</u>:

0.45 molH₂S / 3.0L = 0.15 M

The concentrations at equilibrium would be:

[H₂S] = 0.15 - 2x

[H₂] = 2x

[S₂] = x

We <u>put the data in the Kc expression and solve for x</u>:

\frac{(2x^2) * x}{(0.15-2x)^2}=9.30x10^{-8}

\frac{4x^3}{0.0225-4x^2}=9.30*10^{-8}

We make a simplification because x<<< 0.0225:

\frac{4x^3}{0.0225} =9.30*10^{-8}

x = 8.058x10⁻⁴

[H₂] = 2*x = 1.61x10⁻³ M

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Giving brainiest to whoever answers correctly.
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Answer:250

Explanation:

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stealth61 [152]

Answer:

Explanation:

A substance that produces an excess of hydroxide ion (-OH) in aqueous solution.

       This is an arrhenius Base

According to the arrhenius theory, a base is a substance that combines with water to produce excess hydroxide ions, OH⁻ in an aqeous solution. Examples are :

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An arrhenius acid is a substance that reacts with water to produce excess hydrogen ions in aqueous solutions.

Examples are;

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