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torisob [31]
3 years ago
15

Chemicals A and B react according to the equation A + B → C. How will the concentrations of each component of the reaction chang

e over time?
The concentrations of A and C will increase, while B will decrease.

The concentrations of A and B will decrease, while C will increase.

The concentrations of A, B, and C will decrease.

The concentrations of A, B, and C will increase.
Chemistry
2 answers:
Firlakuza [10]3 years ago
7 0
The concentration of a and b will decrease while c will increase provided all other physical quantities are kept constant in the reaction
Irina18 [472]3 years ago
3 0

Answer:

The correct answer is ;The concentrations of A and B will decrease, while C will increase.

Explanation:

A + B → C

In the given reaction reactant A and B reacts with each other to form product C. As the reaction proceeds the concentration of A and B starts decreasing and concentration of product C increases.

In the end of the reaction concentration of C becomes greater than that of the  A and B concentration

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wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.
Papessa [141]

<u>Answer:</u> The value of equilibrium constant for the net reaction is 11.37

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  A+2B\xrightarrow[]{K_1} 2C

<u>Equation 2:</u>  2C\xrightarrow[]{K_2} D

The net equation follows:

D\xrightarrow[]{K} A+2B

As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K=K_1\times \frac{1}{K_2}

We are given:

K_1=2.57

K_2=0.226

Putting values in above equation, we get:

K=2.57\times \frac{1}{0.226}=11.37

Hence, the value of equilibrium constant for the net reaction is 11.37

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