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solmaris [256]
3 years ago
15

In a store, 1 can of soup costs $1.80. The store also sells a pack 6 cans of soup. A customer who buys 1 pack saves 15% compared

to buying 6 cans separately. How much money does a customer save by buying 1 pack instead of buying 6 cans separately?
Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

\$1.62

Step-by-step explanation:

Let

x-----> the cost of one pack of 6 cans of soup

step 1

Find the cost of 6 cans of soup

6(1.80)=\$10.8

step 2

Find the cost of one pack of 6 cans of soup

100\%-15\%=85\%=85/100=0.85

x=0.85(\$10.8)=\$9.18

step 3

Find the money saved

\$10.8-\$9.18=\$1.62

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A stadium has 50,000 seats. Seats in section A cost $30, seats in section B cost $24, and seats in section C cost $18. the numbe
svetoff [14.1K]

Answer:

Section A = 25,000 seats

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Total Seats = 50,000

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7 0
3 years ago
3.
Vitek1552 [10]
To solve this we are going to use the future value of annuity due formula: FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]
where
FV is the future value
P is the periodic deposit 
r is the interest rate in decimal form 
n is the number of times the interest is compounded per year
k is the number of deposits per year

We know for our problem that P=420 and t=15. To convert the interest rate to decimal form, we are going to divide the rate by 100%: r= \frac{10}{100} =0.1. Since Ruben makes the deposits every 6 months, k=2. The interest is compounded semiannually, so 2 times per year; therefore, k=2.
Lets replace the values in our formula:

FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]
FV=(1+ \frac{0.1}{2} )*420[ \frac{(1+ \frac{0.1}{2})^{(2)(15)}-1 }{ \frac{01}{2} } ]
FV=29299.53

We can conclude that the correct answer is <span>$29,299.53</span>
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