Wayne earns 7%

Mathematics

1 answer:

Ronch [10]2 years ago

7 0

Answer:

Step-by-step explanation:

3500 divided by 5 equals 700

700 times 7% equals 49

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Put in least to highest order 6.86,6.8,7,6.9,6.827 and 12.03,1.2,12.3,1.203,12.301

Anon25 [30]

6.8,6.827,6.86,6.9

1.2,1.203,12.03, 12.301,12.31

6 0

2 years ago

When you were born, your uncle put $1000 into a bank account for you. According to the terms of the account, your investment

kompoz [17]

Answer:

D. Time; amount; $2800

I hope this is right because I was looking for the answer to the same question and this is the solution I came up with.

Step-by-step explanation:

Time is the independent variable because it is the variable that is changed.

The Amount (dollars) is the dependent variable because it is effected by the independent variable.

4 0

2 years ago

Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
$7^{50}=(7^{25})^2$
$7^{25}=7\times(7^{12})^2$
$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$