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Ksivusya [100]
3 years ago
11

A box took five minutes to move. You did 3,150J of work in the process. How much power was required to move the box?

Physics
2 answers:
VLD [36.1K]3 years ago
8 0
Power is energy/time, where t is seconds.  Assuming you were moving the box the whole time, you did 3150/(5*60) = 10.5W
STatiana [176]3 years ago
6 0

Answer:

10.5w

Explanation: power is the ratio of work done in joule with time in seconds.

Therefore,

Power = work done/time

Work done = 3150j

Time = 5×60 = 300s

Power = 3150/300

= 10.5W

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A .005kg projectile leaves a 1500kg launcher with a velocity of 750 m/s. What is the recoil velocity of the projectile
docker41 [41]

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The recoil velocity of the projectile is 0.0025m/s

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The recoil velocity of the projectile = ?

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The recoil velocity is the obtained by dividing the "recoil momentum"  by the "mass of the recoil body".  The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.

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