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2 years ago

The

Chemistry

1 answer:

Vikki [24]2 years ago

5 0

2nd

Explanation:

because i guesses i guess so yeah trust your gut buddy

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1 year ago

The Henry's Law constant of methyl bromide, CH3Br, is KH = 0.159 mol/(L ∙ atm) at 25°C. What is the solubility of methyl bromide

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Henry's law constant for a gas ch3br

28 The Henry's Law constant of methyl bromide, CH3Br, is k = 0.159 mol/(L⋅atm) at 25°C.

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2 years ago

Calculate the [H+] and pH of a 0.0040 M hydrazoic acid solution. Keep in mind that the Ka of hydrazoic acid is 2.20×10−5. Use th

Vera_Pavlovna [14]

Answer:

$[H^+]=0.000285$

$pH=3.55$

Explanation:

In this, we can with the ionization equation for the hydrazoic acid ( $HN_3$ ). So:

$HN_3~~H^+~+~N_3^-$

Now, due to the Ka constant value, we have to use the whole equilibrium because this is not a strong acid. So, we have to write the Ka expression:

$Ka=\frac{[H^+][N_3^-]}{[HN_3]}$

For each mol of $H^+$ produced we will have 1 mol of $N_3^-$ . So, we can use "X" for the unknown values and replace in the Ka equation:

$Ka=\frac{X*X}{[HN_3]}$

Additionally, we have to keep in mind that $HN_3$ is a reagent, this means that we will be consumed. We dont know how much acid would be consumed but we can express a subtraction from the initial value, so:

$Ka=\frac{X*X}{0.004-X}$