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Ann [662]
3 years ago
9

A sample of a compound that contains only the elements C, H, and N is completely burned in O₂ to produce 44.0 g of CO₂, 45.0 g o

f H₂O, and some NO₂ . A possible empirical formula of the compound is ________.
Chemistry
1 answer:
koban [17]3 years ago
3 0

Answer:

CH₅N

Explanation:

In the combustion, all of the C in the compound was used to produce CO₂ in a 1:1 ratio. Thus, the moles of CO₂ (MW 44.01 g/mol) produced equals the moles of C in the compound:

(44.0 g)(mol/44.01g) = 0.99977 mol CO₂ = 0.99977... mol C

Similarly, all of the H in the compound was used to produce H₂O in a ratio of 2H:1H₂O. The moles of H₂O (MW 18.02 g/mol) produced was:

(45.0 g)(mol/18.02g) = 2.497...mol H₂O

Moles of H is found using the molar ratio of 2H:1H₂O:

(2.497...mol H₂O)(2H/1H₂O) = 4.994...mol H

The ratio of H to C in the compound is:

(4.994...mol H)/(0.99977... mol C) = 5 H:C

Some NO₂ was produced from the N in the compound. Assuming a 1:1 ratio of C:N, the simplest empirical formula is: CH₅N.

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What is the density (in g/L) of a gas with
viva [34]

Answer:

2.22 g/L

Explanation:

There's a relationship using the ideal gas law between molar mass and density: MM=\frac{dRT}{P}, where MM is the molar mass, d is the density, R is the gas constant, T is the temperature, and P is the pressure.

We know from the problem that MM = 32.49 g/mol, T = 458 Kelvin, and P = 2.569 atm. The gas constant, R, in terms of the units atm and Kelvin is 0.08206. Let's substitute these values into the formula:

MM=\frac{dRT}{P}

32.49g/mol=\frac{d*0.08206*458K}{2.569atm}

Solve for d:

d * 0.08206 * 458 K = 32.49 * 2.569

d = (32.49 * 2.569) / (0.08206 * 458 K) ≈ 2.22 g/L

The answer is thus 2.22 g/L.

<em>~ an aesthetics lover</em>

4 0
4 years ago
The mass ratio of H:S:O in sulfuric acid today is 1:8:32. Predict the mass ratio of sulfuric acid in 23th century.
lions [1.4K]
You can find the answer on chegg.com. Hope that help :)
8 0
3 years ago
¿Que hace diferente ala química de la alquimia?
viva [34]

Answer:

La distinción entre la química teóricamente teórica y la química avanzada es la química teórica teórica que se basa en un espiritualista, potente que percibe visualmente la autenticidad, mientras que la química espera que la autenticidad sea fundamentalmente mundana. Eso engendra una tremenda distinción, y la química nunca se hubiera alejado excepcionalmente de la remota posibilidad de que se hubiera quedado con el trascendentalismo antediluviano.

Explanation:

8 0
3 years ago
As a chlorine atom becomes a negative ion, the atom
Sav [38]

Answer : The correct option is, (1) Gains an electron and its radius increases.

Explanation :

The given element is chlorine.

Atomic number of chlorine = '17'

The electronic configuration of chlorine is, 1s^22s^22p^63s^23p^5

Number of electrons = 17

Number of protons = 17

The electronic configuration of chloride ion is, 1s^22s^22p^63s^23p^6

Number of electrons = 18

Number of protons = 17

When the chlorine atom gains an electron to acquire a stable electronic configuration. As the electrons add in the valence shell of the chlorine, the number of electrons increases but the number of protons remains the same. So, the protons will not be able to bind the extra electron and it will remain far from the nucleus.

6 0
4 years ago
Read 2 more answers
How many moles of CO2 are produced when 1 mole wax C31H64 is burned?<br><br> 31 32 64 or 47
Lana71 [14]

Answer:

31 moles

Explanation:

The balanced combustion reaction of the wax, C_{31}H_{64} is shown below as:

C_{31}H_{64}+47O_2\rightarrow 31CO_2+32H_2O

As seen from the reaction,

1 mole of wax, C_{31}H_{64} on combustion produces 31 moles of carbon dioxide, CO_2

<u>Hence, moles of CO_2 when 1 mole of wax, C_{31}H_{64} is burnt = 31 moles</u>

4 0
3 years ago
Read 2 more answers
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