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Serhud [2]
2 years ago
13

Does a turtle have a incomplete metamorphosis? its for my little brother

Physics
1 answer:
JulsSmile [24]2 years ago
6 0

Answer:

No. They do not undergo any stage of metamorphosis at all. Once they hatch from their eggs, they remain as the same form for the rest of their life. They grow quite a bit, but they do not "morph", or transform, the way caterpillars turn into butterflies.

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Explain why it is important that the balloon is made from an electrical insulator.
aleksandr82 [10.1K]

Explanation:

object made of rubber, such as the ballons are elecrical insulators, meaning that they resist electric charges flowing through them..

when the ballon has been rubbed enough times to gain a sufficient negative charge, it will be attracted to the wall

8 0
3 years ago
A basketball player throws a ball horizontally toward another player 10 meters away. If the ball is
Nina [5.8K]

Answer:

It will take 0.46 seconds to reach home plate by ball.

Explanation:

7 0
3 years ago
A small particle has charge -2.00 uC and mass 1.50×10-4 kg. It moves from point A, where the electric potential is V(A) = 200 V,
Svet_ta [14]

Answer:

v_b=6.13 m/s..

Explanation:

Since no external force is acting on the system.

Therefore, Total energy remains constant before and after.

So, Total energy of system= energy due to potential applied+kinetic energy

T.E=qV_a+\dfrac{1}{2}mv_a^2=qV_b+\dfrac{1}{2}mv_b^2\\\dfrac{1}{2}mv_b^2=\dfrac{1}{2}mv_a^2+q(V_a-V_b)\\

(Here v=velocity ,V=potential ,q=charge and m=mass).

Putting values .

We get,  v_b=6.13 m/s..

At point B charged particle is moving faster as compared to point A.

Hence, it is the required solution.

5 0
4 years ago
A stone is thrown vertically upward with a speed of 12m/s from the edge of a cliff 70 m high (a) How much later it reaches the b
jonny [76]

Answer

given,

vertical speed of stone,v = 12 m/s

height of the cliff = 70 m

a) time taken by the stone to reach at the bottom of the cliff

We know that,

S = u t + 1/2 a t²

- 70 = 12 t - 0.5 x 9.8 t²

4.9 t² - 12 t - 70 = 0  

solving the equation

t = 5.2 s (neglecting the negative value)

b) again using equation of motion

   v = u + a t

   v = 12 - 9.8 x 5.2

  v = -38.96 m/s

ignoring the negative sign

magnitude of velocity is equal to 38.96 m/s

c) total distance travel by the stone

  vertical distance covered by the stone

 v² = u² + 2 g h

 0 = 12² - 2 x 9.8 x h

 h = 7.34 m

to reach the stone to the same level distance travel be doubled.

Total distance travel by the stone

H = h + h + 70

H = 7.34 x 2 + 70

H = 84.7 m.

8 0
3 years ago
An object 82 cm high forms a virtual image 4.1 cm high located 4.6 cm behind a mirror. Find the object distance.
ioda

Answer:

The object distance is 92 cm.  

Explanation:

let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.

then, the magification of the mirror is given by:

m = -v/u and m = h/H

so, -v/u = h/H

         u = -v×H/h

            = -(-4.6)×(82)/(4.1)

            = 92 cm

Therefore, the object distance is 92 cm.

8 0
3 years ago
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