Answer:
The kinetic energy of bocce ball is more.
Explanation:
Given that,
Mass of a bowling ball, m₁ = 4 kg
Speed of the bowling ball, v₁ = 1 m/s
Mass of bocce ball, m₂ = 1 kg
Speed of bocce ball, v₂ = 4 m/s
We need to say which has more kinetic energy.
The kinetic energy of an object is given by :
Kinetic energy of the bowling ball,
The kinetic energy of the bocce ball,
So, the kinetic energy of bocce ball is more than that of bowling ball.
Answer:
It is possible by increasing the speed of the tennis ball by a factor of (Mass of the tennis ball)/(Mass of the basketball)
Explanation:
The momentum of a body = The bod's mass × The body's velocity
Therefore, the momentum of a given mass of an object, such as a tennis ball can be increased by increasing the velocity or speed of the object. Whereby the speed of the ball, v₁, is increased such that the momentum of the basketball and the tennis ball will be the same, is given by the following equation
Mass of the basketball × v₂ = Mass of the tennis ball × v₁
Therefore, v₁/v₂ = (Mass of the tennis ball)/(Mass of the basketball)
Answer:
The necessary information is if the forces acting on the block are in equilibrium
The coefficient of friction is 0.577
Explanation:
Where the forces acting on the object are in equilibrium, we have;
At constant velocity, the net force acting on the particle = 0
However, the frictional force is then given as
F = mg sinθ
Where:
m = Mass of the block
g = Acceleration due to gravity and
θ = Angle of inclination of the slope
F = 5×9.81×sin 30 = 24.525 N
Therefore, the coefficient of friction is given as
24.525 N = μ×m×g × cos θ = μ × 5 × 9.81 × cos 30 = μ × 42.479
μ × 42.479 N= 24.525 N
∴ μ = 24.525 N ÷ 42.479 N = 0.577
Answer:
4v/3
Explanation:
Assume elastic collision by the law of momentum conservation:
where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively
Substitute 
Divide both side by 
, then multiply by 6 we have
So the final speed of the second car is 4/3 of the first car original speed
Answer:
Part a)
Part b)
So this speed is independent of the mass of the rider
Explanation:
Part a)
By force equation on the rider at the position of the hump we can say
now we will have
now we have
Part b)
At the top of the loop if the minimum speed is required so that it remains in contact so we will have
at minimum speed
So this speed is independent of the mass of the rider
