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4 years ago

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A rocky space object of varying size

1 answer:

kow [346]4 years ago

3 0

That would be an asteroid

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A car is raised on a lift at a service station (so it has some amount of gravitational potential energy relative to the ground).

kenny6666 [7]

Answer:Twice

Explanation:

It is given that car is raised on a lift with respect to ground.

Suppose car is raised by a height of h m from ground having mass m so gain in Potential Energy by car is

Gain in $P.E._1=m\times g\times h$

Now if it were raised twice as high,i.e. 2 h height from ground then gain in Gravitational Potential Energy

$=m\times g\times 2h$

$P.E._2=2m\cdot g\cdot h$

It is clear that $P.E._2=2\cdot P.E._1$

Thus in second case gain in Potential Energy is twice as compared to first case

8 0

4 years ago

Plz help me answer this question if u answer them all correctly and respectfuly i will make u brainliest.

Musya8 [376]

Please explain more pls

6 0

3 years ago

A straight wire lies along the y-axis initially carrying a current of 10 A in the positive y-direction. The current decreases an

Elan Coil [88]

Answer:

Explanation:

The magnetic field due to straight wire is into the square coil.

As the current in straight wire decreases the magnetic flux in the coil decreases . The induced magnetic field is into the coil.The induced current is along +y direction

8 0

4 years ago

A composite load consists of three loads connected in parallel. One draws 100 W at a PF of 0.92 lagging, another takes 250 W at

fenix001 [56]

Answer:

a) $I_{RMS} = 4.79 A$

b) $PF = 0.908$

Explanation:

Get the reactive powers for each of the loads:

Reactive power = Real Power * tanθ

For load 1

Active power, P₁ = 100 W

Power factor, $cos \theta_{1} = 0.92$

$\theta_{1} = cos^{-1} 0.92\\\theta_{1} = 23.074$

$Q_{1}= P_{1} tan \theta_{1} \\Q_{1}= 100tan 23.074\\Q_{1}= 42.60 W$

For load 2

Active power, P₂ = 250 W

Power factor, $cos \theta_{2} = 0.8$

$\theta_{2} = cos^{-1} 0.8\\\theta_{2} = 36.87$

$Q_{2}= P_{1} tan \theta_{2} \\Q_{2}= 250tan 36.87\\Q_{2}= 187.5 W$

For load 3

Active power, P₃ = 250 W

Power factor, $cos \theta_{3} = 1$

$\theta_{3} = cos^{-1} 1\\\theta_{3} =0$

$Q_{2}= P_{1} tan \theta_{3} \\Q_{3}= 150tan 0\\Q_{3}= 0 W$

Calculate the total reactive power, $Q_{net} = 42.6 + 187.5 + 0$

$Q_{net} = 230.1 W$

Calculate the total active power, $P_{net} = 100 + 250 + 150 = 500 W$

$S_{net} = P_{net} + Q_{net} \\S_{net} = 500 + j230.1$

$P_{net} = IVcos \theta_{net}$

$\theta_{net} = tan^{-1} \frac{230.1}{500} \\\theta_{net} = 24.712$

V = 115 $V_{rms}$

$500 = I_{RMS} * 115 cos 24.712\\I_{RMS} = 500/104.47\\ I_{RMS} = 4.79 A$

b) Power factor of the composite load is $cos\theta_{net}$

$\theta_{net} = 24.712\\PF = cos 24.712\\PF = 0.908$

4 0

3 years ago

Hi guys. Im doing a project at school where we have to create a mouse trap powered car. I wanted to know what materials are a mu

natta225 [31]

Depends on how heavy ur car is, u could use a high powered fan to move the can or u could use the motor and wheels from a remote control car

4 0

3 years ago