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erastova [34]
3 years ago
9

8459299

Physics
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

Mechanical energy is the energy that is possessed by an object due to its motion or due to its position. Mechanical energy can be either kinetic energy (energy of motion) or potential energy

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If u blow a stream of air between two balloons that are next to each other the balloons
Naya [18.7K]

Answer:

move towards each other

Explanation:

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The number of kilograms of water in a human body varies directly as the mass of the body. Upper AA 9393​-kg person contains 6262
Pie

Answer:

54 kg

Explanation:

Mass of person = 93 kg = m_p

Mass of water = 62 kg = m_w

Dividing the above two masses we get

\frac{m_p}{m_w}=\frac{93}{62}\\\Rightarrow \frac{m_p}{m_w}=1.5\\\Rightarrow m_p=1.5m_w

Hence, the mass of the person is 1.5 times the mass of the water in them

Now, Mass of person = 81 kg = m_p

m_p=1.5m_w\\\Rightarrow m_w=\frac{1}{1.5} m_p\\\Rightarrow m_w=\frac{1}{1.5} \times 81\\\Rightarrow m_w=54\ kg

So, the mass of water in a person that has mass of 81 kg is 54 kg

3 0
3 years ago
What word chemical equation describes second chemical reaction
finlep [7]

Production

Explanation:

Because it is what the frist chemical equation equation or reactant turns into

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What pattern does the earth revolve around the sun?.
Whitepunk [10]

Answer: The Earth moves around the Sun in an extended circular or oval pattern. Or otherwise known as an "elliptical" orbit.

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Calculate the Reynolds number for an oil gusher that shoots crude oil 25.0 m into the air through a pipe with a 0.100-m diameter
Alenkasestr [34]

Answer:

Re=1992.24

Explanation:

Given:

vertical height of oil coming out of pipe, h=25\ m

diameter of pipe, d=0.1\ m

length of pipe, l=50\ m

density of oil, \rho = 900\ kg.m^{-3}

viscosity of oil, \mu=1\ Pa.s

Now, since the oil is being shot verically upwards it will have some initial velocity and will have zero final velocity at the top.

<u>Using the equation of motion:</u>

v^2=u^2-2gh

where:

v = final velocity

u = initial velocity

Putting the respective values:

0^2=u^2-2\times 9.8\times 25

u=22.136\ m.s^{-1}

<u>For Reynold's no. we have the relation as:</u>

Re=\frac{\rho.u.d}{\mu}

Re=\frac{900\times 22.136\times 0.1}{1}

Re=1992.24

6 0
3 years ago
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