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3 years ago

How much work is done to move 3c of charge through a potential difference of 1.5v

Physics

1 answer:

kaheart [24]3 years ago

4 0

Answer:4.5 joules

Explanation:

charge=3c

Potential difference=1.5v

Work=potential difference x charge

Work=1.5 x 3

Work=4.5

Work=4.5 joules

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The total negative charge on the electrons in 1mol of helium (atomic number 2, molar mass 4) is ________?

DaniilM [7]

Answer:

$1.92\times 10^5 C$

Explanation:

We are given that

Atomic number=2

We have to find the total negative charge on the electrons in one mole of Helium.

We know that atomic number=Proton number

Proton number=Number of electrons=2

Number of electrons in Helium=2

1 mole of Helium= $6.02\times 10^{23}$ atoms

We know that q=ne

Where n =Number of fundamental units

e=Charge on electron

1 e= $1.6\times 10^{-19}C$

Using the formula

$q=2\times 1.6\times 10^{-19}=3.2\times 10^{-19}C$

Total negative charge in 1 mole= $3.2\times 10^{-19}\times 6.02\times 10^{23}=1.92\times 10^5C$

Hence, the total negative charge on the electrons in 1 mole of Helium= $1.92\times 10^5 C$

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3 years ago

A sample of a diatomic ideal gas has pressure P and volume V. When the gas is warmed, its pressure triples and its volume double

Andreyy89

Answer:

Amount of Energy transferred $=8.5PV$

Explanation:

Given:

Initial volume=V

Initial pressure=P

Final volume=2V

Final pressure=3P

Now w know that the Energy transferred in constant pressure pressure is given by

$E_1=nc_pdT\\\\E_1=n\times\dfrac{7R}{2}dT\\E_1=3.5(nRdT)\\E_1=3.5(V(2P-P))\\E_1=3.5PV$

Now the Energy transferred in constant volume process is given by

$E_2=nc_vdT\\\\E_2=n\times\dfrac{5R}{2}dT\\E_1=2.5(nRdT)\\E_1=2.5(V(3V-V))\\E_1=5PV$

The total Energy transferred is given by

$E_{total}=E_1+E_2\\E{total}=3.5PV+5PV\\=8.5PV$

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