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2 years ago

PLEASE HELP ASAP!!!!!!!!!!!!! I dont understand this stuff at all.........

1 answer:

4 0

At a depth of 34 feet the diver experiences 2 atmospheres of pressure. At a depth of 68 feet the diver is experiencing 3 atmospheres. At a depth of 102 feet the diver is experiencing 4 atmospheres of pressure. At one atmosphere of pressure the body is mildy compressed. As the diver descends the divers body will undergo increased compression instead of being squashed.

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How many molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium? 4na o2 -> 2na2o

Leona [35]

Molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium will be 7.04 × 10 ²⁴ molecules.

Sodium oxide is Na₂O which is formed due to the reaction of sodium and oxygen.

Given,

Balanced chemical equation is :

4 Na(s) + O₂ (g) → 2Na₂O (s)

Now, the Mole ratio of O₂ and Na₂O is 1 mol O₂: 2 mol Na₂O

Molar mass O₂ = 32.00 g/mol

Now, let's find out the Number of moles of O₂ present in 187 grams of oxygen,

Number of moles of O₂ = Given mass in grams / molar mass of O₂

Number of moles of O₂ = 187 g / 32.00 g/mol

Number of moles of O₂ = 5.844 mol

Since, we know the Proportion is 1 mol O₂ : 2 mol Na₂O

Now, Number of moles of Na₂O required is,

2 mol Na₂O / 1 mol O₂ = 5.844 mol O₂ / x

x = 5.844 mol O₂ (2 mol Na₂O / 1 mol O₂)

x = 11.688 mol Na₂O

To calculate the Number of molecules of sodium oxide,

Number of molecules = Number of moles × Avogadro's number

Number of molecules = 11.688 mol × 6.022 × 10²³ molecules/mol =

Number of molecules = 7.04 × 10 ²⁴ molecules

Hence, the Number of molecules of sodium oxide required is 7.04 × 10²⁴ molecules.

Learn more about Sodium oxide here,

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3 0

1 year ago

Consider the intermediate chemical reactions. 2 equations. First: upper C a (s) plus upper C upper O subscript 2 (g) plus one ha

DochEvi [55]

Answer: When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The overall chemical reaction follows:

$CaO(s)+CO_2\rightarrow CaCO_3(s)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)$ $\Delta H_1=-812.8kJ$

(2) $2Ca(s)+O_2(g)\rightarrow 2CaO(s)$ $\Delta H_2=-1269kJ$

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[\frac{1}{2}\times (-\Delta H_2)]$

Hence, when the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

3 0

2 years ago

How many grams of sodium are in .500 of a mole

Step2247 [10]

Convert mole to gram by multiplying the molar mass of sodium

0.500mol Na x 22.990g = 11.495g of Na

4 0

2 years ago

1. Cp is smaller than Hx

andreev551 [17]

1 has a higher ionization dismal aoa

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2 years ago

All STEM subjects require ________________ skills. a. Same b. Different

Andreyy89

B different skills as every subject varies from each other

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3 years ago