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3 years ago

PLEASE HELP ASAP!!!!!!!!!!!!! I dont understand this stuff at all.........

1 answer:

4 0

At a depth of 34 feet the diver experiences 2 atmospheres of pressure. At a depth of 68 feet the diver is experiencing 3 atmospheres. At a depth of 102 feet the diver is experiencing 4 atmospheres of pressure. At one atmosphere of pressure the body is mildy compressed. As the diver descends the divers body will undergo increased compression instead of being squashed.

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No links right answers only!! 9recipitation like in the Arctic tundra.

erik [133]

The answer is. B hope it helps plz mark me a brainless plz

4 0

3 years ago

Read 2 more answers

What is the concentration of NaCl in a solution if titration of 15.00 mL of the solution with 0.2503 M AgNO3 requires 20.22 mL o

Nina [5.8K]

Answer:

The concentration of NaCl = 0.3374 M

Explanation:

Given :

Molarity of AgNO₃ = 0.2503 M

Volume of AgNO₃ = 20.22 mL

The conversion of mL into L is shown below:

$1 mL= 10^{-3} L$

Thus, volume of the solution = 20.22×10⁻³ L

Molarity of a solution is the number of moles of solute present in 1 L of the solution.

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

The formula can be written for the calculation of moles as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Thus,

$Moles\ of\ AgNO_3 =Molarity \times {Volume\ of\ the\ solution}$

$Moles\ of\ AgNO_3 =0.2503 \times {20.22\times 10^{-3}}\ moles$

$Moles\ of\ AgNO_3 = 5.0611 \times 10^{-3} moles$

The chemical reaction taking place:

$AgNO_3_(aq) + NaCl_(aq) \rightarrow AgCl_(s) + NaNO_3_(aq)$

According to reaction stoichiometry:

1 mole of AgNO₃ reacts with 1 mole of NaCl

Thus,

5.0611×10⁻³ moles of AgNO₃ reacts with 5.0611×10⁻³ moles of NaCl

Thus, moles of NaCl required = 5.0611×10⁻³ moles

Volume of NaCl required = 15.00 mL

The conversion of mL into L is shown below:

$1 mL= 10^{-3} L$

Thus, volume of the solution = 15.00×10⁻³ L

Applying in the formula of molarity as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity\ of\ NaCl=\frac{5.0611\times 10^{-3}}{15.00\times 10^{-3}}$

$Molarity\ of\ NaCl= 0.3374 M$

Thus, the concentration of NaCl = 0.3374 M

6 0

3 years ago

5) 3Na2SO4

xenn [34]

Answer:

3Na2SO4

Explanation:

3Na2SO4

# of molecules: 3 moles of Na2SO4 or 3 × 6.22 × 10^23 molecules.

# of elements: 3 elements l

Name of element: = Sodium, S = Sulphur, O = Oxygen

# of atoms: Na = 6 atoms, S= 3, O= 12

Total # of atoms: 21

The #3 is a Coefficient.

Please mark branliest if you are satisfied. Thanking in anticipation.

7 0

2 years ago

Determine the volume, in liters, of 3.2 mol of CO2 gas at STP.

Allushta [10]

Answer:

71.7 L

Explanation:

Using the ideal gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/Kmol)

T = temperature (K)

According to the information provided in this question;

P = 1 atm (STP)

V = ?

n = 3.2mol

T = 273K (STP)

Using PV = nRT

V = nRT/P

V = 3.2 × 0.0821 × 273/1

V = 71.7 L

6 0

3 years ago

Which of the following is most likely to occur if the organ labeled 1 stops working correctly?

Dafna1 [17]

theres no link or pictureeee

6 0

3 years ago