Answer: Volume of 1g of pure gold 
Given;
Density of a pure gold=19.3 
Mass of a pure gold =1g
To find:
Volume of 1g of pure gold
Solution:
According to the formula,
Density= Mass/Volume
Where 
=density of pure gold
m=mass of pure gold
v=volume of pure gold
From the above equation volume can be calculated as
Substitute the values of mass and density value in the above equation
Result:
Thus the volume of 1g of pure gold is
In a place with no gravity
Explanation:
Weight is a force exerted by a body in the presence of gravity.
Weight = mass x gravity
Without gravity, there is no force of weight. The more the gravity, the more the weight of a body.
A body will experience weightlessness in a place without no gravity.
Therefore, one will experience the least weight in a place without the pull of gravity.
Learn more:
weight and mass brainly.com/question/5956881
#learnwithBrainly
The correct answer is a.) C. Oxidation occurs when an element loses electrons and increases its oxidation state. In the chemical equation, Carbon in CH4 has an oxidation state of 4- while Carbon in CO2 has an oxidation of 4+.
The highest sequence for this shell is the number 2, preceding both the s and p in the diagram. This means that the outermost shell is the second level shell. In this shell, there are 7 electrons, 2 in the 2s orbital and 5 in the 2p orbital.
As a side note (not sure if this is a typo), the electron structure for fluorine begins with a 1s2, not a 1s1.
A) Mass Number
B) Protons and Electrons
C) (I think group but I'm not 100% sure on this...)
D) 12 (To work out the number of neutrons you do MASS number - ATOMIC number aka the number of protons so in this case you'd do 23-11=12)
Hope this helps
