Any collection of data or information that has been properly structured for quick search and retrieval by a computer is referred to as a database, often known as an electronic database.
<h3>What is electronic database?</h3>
- Databases are designed to make it easy to save, retrieve, edit, and delete data while carrying out various data-processing tasks. In response to queries, a database management system (DBMS) retrieves data from the database.
- Databases are briefly discussed after that. See computer science: Information systems and databases; information processing for a comprehensive explanation.
- A file or collection of files used to store a database.
- These files' contents can be divided up into records, each of which has one or more fields.
- The fundamental units of data storage are fields, and each field typically contains data related to one feature or attribute of the thing that the database is describing.
- Additionally, records are arranged into tables that contain details on the connections between their various fields.
- A database in the strict sense offers cross-referencing capabilities, despite the fact that the term "database" is used broadly to refer to any collection of information in computer files.
- Users can quickly search, rearrange, organize, and choose the fields in numerous records to access or produce reports on certain data aggregates using keywords and a variety of sorting instructions.
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Answer:
1200KJ
Explanation:
The heat dissipated in the rotor while coming down from its running speed to zero, is equal to three times its running kinetic energy.
P (rotor-loss) = 3 x K.E
P = 3 x 300 = 900 KJ
After coming to zero, the motor again goes back to running speed of 1175 rpm but in opposite direction. The KE in this case would be;
KE = 300 KJ
Since it is in opposite direction, it will also add up to rotor loss
P ( rotor loss ) = 900 + 300 = 1200 KJ
Answer with Explanation:
Part a)
The volume of water in the tank as a function of time is plotted in the below attached figure.
The vertical intercept of the graph is 46.
Part b)
The vertical intercept represents the volume of water that is initially present in the tank before draining begins.
Part c)
To find the time required to completely drain the tank we calculate the volume of the water in the tank to zero.
Part d)
The horizontal intercept represents the time it takes to empty the tank which as calculated above is 13.143 minutes.
Answer:
The radius of a wind turbine is 691.1 ft
The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m
Explanation:
Given;
power generation potential (PGP) = 1000 kW
Wind speed = 5 mph = 2.2352 m/s
Density of air = 0.0796 lbm/ft³ = 1.275 kg/m³
Radius of the wind turbine r = ?
Wind energy per unit mass of air, e = E/m = 0.5 v² = (0.5)(2.2352)²
Wind energy per unit mass of air = 2.517 J/kg
PGP = mass flow rate * energy per unit mass
PGP = ρ*A*V*e
r = 210.64 m = 691.1 ft
Thus, the radius of a wind turbine is 691.1 ft
PGP = CVᵃ
For best design of wind turbine Betz limit (c) is taken between (0.35 - 0.45)
Let C = 0.4
PGP = Cvᵃ
take log of both sides
ln(PGP) = a*ln(CV)
a = ln(PGP)/ln(CV)
a = ln(1000)/ln(0.4 *2.2352) = 7.73
The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m
