Answer:
peak flow and any engineering considerations related thereto
Explanation:
It should be no surprise that a peak flow meter will report peak flow, sometimes with important maximum-value, time-constant, or bandwidth limitations. There are many engineering issues related to flow rates. A peak flow meter can allow you to assess those issues with respect to the flows actually encountered.
Peak flow can allow you to assess adequacy of flow and whether there may be blockages or impediments to flow that reduce peak levels below expected values. An appropriate peak flow meter can help you assess the length of time that peak flow can be maintained, and whether that delivers sufficient volume.
It can also allow you to assess whether appropriate accommodation is made for unexpectedly high flow rates. (Are buffers or overflow tanks of sufficient size? Is there adequate protection against possible erosion? Is there adequate support where flow changes direction?)
Answer:
From the main bearings, the oil passes through feed-holes into drilled passages in the crankshaft and on to the big-end bearings of the connecting rod.
Answer:
The correct answer is: The process equation is PV^n=C
Explanation:
The isothermal process drops the pressure slower with n=1 and region beneath the curve is smaller then, meanwhile the polytropic process with n=1.25 gets to drop the pressure faster than isothermal.
The amount of settlement that would occur at the end of 1.5 year and 5 year are 7.3 cm and 13.14 cm respectively.
<h3>How to determine the amount of settlement?</h3>
For a layer of 3.8 m thickness, we were given the following parameters:
U = 50% = 0.5.
Sc = 7.3 cm.
For Sf, we have:
Sf = Sc/U
Sf = 7.3/0.5
Sf = 14.6
Therefore, Sf for a layer of 38 m thickness is given by:
Sf = 14.6 × 38/3.8
Sf = 146 cm.
At 50%, the time for a layer of 3.8 m thickness is:
= 1.5 year.
At 50%, the time for a layer of 38 m thickness is:
= 1.5 × (38/3.8)²
= 150 years.
For the thickness of 38 m, U₂ is given by:
![\frac{U_1^2}{U_2^2} =\frac{(T_v)_1}{(T_v)_2} = \frac{t_1}{t_2} \\\\U_2^2 = U_1^2 \times [\frac{t_2}{t_1} ]\\\\U_2^2 = 0.5^2 \times [\frac{1.5}{150} ]\\\\U_2^2 = 0.25 \times 0.01\\\\U_2=\sqrt{0.0025} \\\\U_2=0.05](https://tex.z-dn.net/?f=%5Cfrac%7BU_1%5E2%7D%7BU_2%5E2%7D%20%3D%5Cfrac%7B%28T_v%29_1%7D%7B%28T_v%29_2%7D%20%3D%20%5Cfrac%7Bt_1%7D%7Bt_2%7D%20%5C%5C%5C%5CU_2%5E2%20%3D%20U_1%5E2%20%5Ctimes%20%5B%5Cfrac%7Bt_2%7D%7Bt_1%7D%20%5D%5C%5C%5C%5CU_2%5E2%20%3D%200.5%5E2%20%5Ctimes%20%5B%5Cfrac%7B1.5%7D%7B150%7D%20%5D%5C%5C%5C%5CU_2%5E2%20%3D%200.25%20%20%5Ctimes%200.01%5C%5C%5C%5CU_2%3D%5Csqrt%7B0.0025%7D%20%5C%5C%5C%5CU_2%3D0.05)
The new settlement after 1.5 year is:
Sc = U₂Sf
Sc = 0.05 × 146
Sc = 7.3 cm.
For time, t₂ = 5 year:
![U_2^2 = U_1^2 \times [\frac{t_2}{t_1} ]\\\\U_2^2 = 0.5^2 \times [\frac{5}{150} ]\\\\U_2^2 = 0.25 \times 0.03\\\\U_2=\sqrt{0.0075} \\\\U_2=0.09](https://tex.z-dn.net/?f=U_2%5E2%20%3D%20U_1%5E2%20%5Ctimes%20%5B%5Cfrac%7Bt_2%7D%7Bt_1%7D%20%5D%5C%5C%5C%5CU_2%5E2%20%3D%200.5%5E2%20%5Ctimes%20%5B%5Cfrac%7B5%7D%7B150%7D%20%5D%5C%5C%5C%5CU_2%5E2%20%3D%200.25%20%20%5Ctimes%200.03%5C%5C%5C%5CU_2%3D%5Csqrt%7B0.0075%7D%20%5C%5C%5C%5CU_2%3D0.09)
The new settlement after 5 year is:
Sc = U₂Sf
Sc = 0.09 × 146
Sc = 13.14 cm.
Read more on clay layer here: brainly.com/question/22238205
Answer:
Shining lantern Magic beans
Explanation:
I will explain the code line by line.
The first statement contains a string type variable magicPowers and second statement has an int type variable experienceLevel which is initialized by value 9.
Nested if statement are used and lets see which of those statements execute.
The first if statement checks if the value of experienceLevel is greater than 10. This statement evaluates to false because the value of experienceLevel is set to 9. Then the program control moves to the next if statement.
The second if statement checks if the value of experienceLevel is greater than 8. This if condition evaluates to true because the value of experienceLevel is 9. So this if statement is executed which contains the statement magicPowers = magicPowers + "Shining lantern "; . This means magicPowers stores the string Shining lantern.
The third if statement checks if the value of experienceLevel is greater than 2. As the value of experienceLevel is 9 so this condition also evaluates to true which means the statement magicPowers = magicPowers + "Magic beans "; is executed. This statement means magicPowers stores the string Magic Beans
You can use a print statement to display the output on the screen as:
System.out.print(magicPowers);
Output:
Shining lantern Magic beans
The program along with the output is attached as a screenshot.