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Natasha_Volkova [10]
3 years ago
12

جائت فكرة ربط الحواسيب لغرض نقل البيانات و مشاركتها و بعدها بفتره قصيره جائت إمكانية مشاركة الموارد بين الحواسيب صح ام خطأ​

Engineering
2 answers:
melamori03 [73]3 years ago
5 0

Answer:

بدلاً من ذلك يُشار إليه باسم مشاركة أو مشاركة شبكة ، الدليل المشترك هو دليل أو مجلد يمكن الوصول إليه من قبل العديد من المستخدمين على الشبكة. هذه هي الطريقة الأكثر شيوعًا للوصول إلى المعلومات ومشاركتها على شبكة محلية

Explanation:

Lubov Fominskaja [6]3 years ago
5 0

أعتقد أن هذا صحيح. أتمنى أن يساعدك هذا!

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Air is compressed adiabatically from p1 1 bar, T1 300 K to p2 15 bar, v2 0.1227 m3 /kg. The air is then cooled at constant volum
sashaice [31]

Answer:

Work done for the adiabatic process = -247873.6 J/kg = - 247.9 KJ/kg

Heat transfer for the constant volume process = - 244.91 KJ/kg

Explanation:

For the first State,

P₁ = 1 bar = 10⁵ Pa

T₁ = 300 K

V₁ = ?

Second state

P₂ = 15 bar = 15 × 10⁵ Pa

T₂ = ?

V₂ = 0.1227 m³/kg

Third state

P₃ = ?

T₃ = 300 K

V₃ = ?

We require the workdone for step 1-2 (which is adiabatic)

And heat transferred for steps 2-3 (which is isochoric/constant volume)

Work done for an adiabatic process is given by

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

where γ = ratio of specific heats = 1.4 for air since air is mostly diatomic

K = PVʸ

Using state 2 to calculate for k

K = P₂V₂ʸ = (15 × 10⁵)(0.1227)¹•⁴ = 79519.5

We also need V₁

For an adiabatic process

P₁V₁ʸ = P₂V₂ʸ = K

P₁V₁ʸ = K

(10⁵) (V₁¹•⁴) = 79519.5

V₁ = 0.849 m³/kg

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

W = 79519.5 [(0.1227)⁻⁰•⁴ - (0.849)⁻⁰•⁴]/(1 - 1.4)

W = (79519.5 × 1.247)/(-0.4) = - 247873.6 J/kg = - 247.9 KJ/kg

To calculate the heat transferred for the constant volume process

Heat transferred = Cᵥ (ΔT)

where Cᵥ = specific heat capacity at constant volume for air = 0.718 KJ/kgK

ΔT = T₃ - T₂

We need to calculate for T₂

Assuming air is an ideal gas,

PV = mRT

T = PV/mR

At state 2,

V/m = 0.1227 m³/kg

P₂ = 15 bar = 15 × 10⁵ Pa

R = gas constant for air = 287.1 J/kgK

T₂ = 15 × 10⁵ × 0.1227/287.1 = 641.1 K

Q = 0.718 (300 - 641.1) = - 244.91 KJ/kg

7 0
3 years ago
Which of the following is an example of a civil engineer demonstrating problem sensitivity? (Select all that apply.)
zaharov [31]

Answer:

all of the above hidtsybkhitonp

Explanation:

nyppinnoxtstuity433ongdhfkgt

8 0
3 years ago
Using what you know about the NAND gate, draw how you could implement a three-input NAND gate using NMOS and PMOS transistors. T
Yuliya22 [10]

Answer:

use this, it should help you understand

Explanation:

https://www.electronics-tutorials.ws/logic/logic_5.html

4 0
3 years ago
Suspension cultures of Panax ginseng plant cells are used to produce ginseng biomass for the health tonic market. The cells are
slavikrds [6]

<u>Solution and Explanation:</u>

When using a larger vessel that still requires heating, temperature control measures can be required to provide the initial heat requirement, as well as provide the necessary chilling capacity.

• If the lowest temperature point is near or below ambient and the reaction is exothermic, or a controlled temperature change from high to low is required, then a bath circulator with refrigeration for small vessels or a larger chiller will be required.

In order to calculate the required heating or cooling capacity to reach the desired temperature, the heat load comprised of the specific internal energy must be determined.

This is the energy associated with a change in temperature of a given mass, where no electrical, mechanical or chemical energy is being added to the system. The final calculations include everything that is being cooled or heated, including the culture medium, the bioreactor, the fluid in the jacket, plumbing lines and temperature control unit.

The heat load calculation

Q = MCΔT

Q = heat load (Kilocalories/Kcal)

M = Mass of the substance that is changing temperature (kg)

C = specific heat of the substance that is changing temperature (calories/gram, /°Kelvin)

ΔT = change in temperature (°C)

Once the desired temperature or temperature range and heat load have been determined, and manipulated to compensate for the desired time frame, you will need to estimate the additional cooling or heating needed to poor heat transfer and heat gained from, or lost to the external environment.

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3 years ago
An environmental engineer is considering three methods for disposing of a nonhazardous chemical sludge: land application, fluidi
padilas [110]

Answer:

Explanation:

The annual worth of land application = $ 110,000 ( A/P , 10% , 5 years ) + $ 95,000 - $ 15,000 (A/F , 10% , 5 years )

The annual worth of land application = $ 110,000 X 0.263797 + $ 95,000 - $ 15,000 X 0.163797

The annual worth of land application = $ 29,017.54 + $ 95,000 - $ 2,456.95

The annual worth of land application = $ 121,560.59

The annual worth of land Incineration = $ 800,000 ( A/P , 10% , 6 years ) + $ 60,000 - $ 250,000 X (A/F , 10% , 6 years )

The annual worth of land Incineration = $ 800,000 X 0.229607 + $ 60,000 - $ 250,000 X 0.129607

The annual worth of land Incineration = $ 211,283.85

The annual worth of contract = $ 190,000

The annual worth of contract = $ 190,000

The land application has the least cost , hence it is preferred .

5 0
3 years ago
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