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AVprozaik [17]
3 years ago
5

You buy a 75-W lightbulb in Europe, where electricity is delivered to homes at 240V. If you use the lightbulb in the United Stat

es at 120 V (assume its resistance does not change), how bright will it be relative to 75-W 129-V bulbs?
Engineering
1 answer:
givi [52]3 years ago
7 0

Answer:

The bulb will be \frac{1}{4} times as bright as it is in Europe.

Explanation:

Data provided in the question:

Power of bulb in Europe = 75 W

Voltage provided in Europe = 240 V

Voltage provided in United Stated = 120 V

Now,

We know,

Power = Voltage² ÷ Resistance

Therefore,

75 = 240² ÷ Resistance

or

Resistance = 240² ÷ 75

or

Resistance = 768 Ω

Therefore,

Power in United States = Voltage² ÷ Resistance

= 120² ÷ 768

= 18.75 W

Therefore,

Ratio of powers

\frac{\text{Power in united states}}{\text{Power in Europe}}=\frac{18.75}{75}

= \frac{1}{4}

Hence,

The bulb will be \frac{1}{4} times as bright as it is in Europe.

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Answer:

P = 150.335\,kPa (Option B)

Explanation:

The absolute pressure of the air-filled tank is:

P = 101.3\,kPa + \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{kg}{m^{3}} \right)\cdot (5\,m)\cdot \left(\frac{1\,kPa}{1000\,Pa} \right)

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3 years ago
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John wants to construct a device using quartz crystal, Which device can he construct?
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3 years ago
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3 0
3 years ago
From an aerial photograph, one observes that on a level section of a (multilane) highway, 25% of the vehicles are trucks, 75% ar
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Answer:

(a) Flow rate of vehicles = No of vehicles per mile * Speed

=No of cars per mile * Speed +No of trucks per mile * Speed

= 0.75*50*60 + 0.25*50*40

=2750 vehicles / hour

(b) Let Density of vehicles on grade = x

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3 years ago
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