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3 years ago

Table 2 Heat of Reaction of NaOH (aq) and HCl(aq) Solution

Chemistry

1 answer:

kondaur [170]3 years ago

8 0

Answer:

the molarity of NaOH is 1.10. And the molarity of HCl is 1.10. And the initial Temp=0.50(°c). and The final Temp= 1.10(°c)

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How many atoms are in 10.1 g Ne

LekaFEV [45]

Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Tables
Moles

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[Given] 10.1 g Ne

[Solve] atoms Ne

Step 2: Identify Conversions

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

Step 3: Convert

[DA] Set up: $\displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

4 0

3 years ago

What is atom ? chemistry

Neporo4naja [7]

Answer:

atom is the smallest unit of matter that has the characteristic properties of a chemical element.

3 0

3 years ago

Looking at the periodic table, which of these elements has the smallest atomic radius?

Sauron [17]

Helium
Remember: electron filling of atomic shell ...
The element which have electron in the lowest quantum shell will have the smallest atomic radius\

He:1s1 (Helium)

H:1s2 (hydrogen)

8 0

3 years ago

A metal ion Mⁿ⁺ has a single electron. The highest energy line in its emission spectrum occurs at a frequency of 2.961 x 10¹⁶ Hz

Whitepunk [10]

Answer:

z≅3

Atomic number is 3, So ion is Lithium ion ( $Li^+$ )

Explanation:

First of all

v=f*λ

In our case v=c

c=f*λ

λ=c/f

where:

c is the speed of light

f is the frequency

$\lambda=\frac{3*10^8}{2.961*10^{16}}\\ \lambda=1.01317*10^{-8} m$

Using Rydberg's Formula:

$\frac{1}{\lambda}=R*z^2*(\frac{1}{n_1^2}-\frac{1}{n_2^2})$

Where:

R is Rydberg constant= $1.097*10^7$

z is atomic Number

For highest Energy:

n_1=1

n_2=∞

$\frac{1}{1.01317*10^{-8}}=1.097*10^{7}*z^2*(\frac{1}{1^2}-\frac{1}{\inf})\\z^2=8.99\\z=2.99$

z≅3

Atomic number is 3, So ion is Lithium ion ( $Li^+$ )

3 0

3 years ago

Determine the amount of energy (heat) in joules required to raise the temperature of 20g of gold from 5°C to 37°C.

insens350 [35]

Answer:

The answer to your question is E = 83.2 J

Explanation:

Data

Element: Gold

Initial temperature = T1 = 5°C

Final temperature = T2 = 37°C

mass = 20 g

Specific heat = 130 J/kg°K

Process

1.- Convert temperature to kelvin

T1 = 273 + 5 = 278°K

T2 = 273 + 37 = 310°K

2.- Convert mass to kg

1000 g --------------- 1 kg

20 g --------------- x

x = (20 x 1)/1000

x = 0.02 kg

3.- Formula

E = mC(T2 -T1)

4.- Substitution

E = (0.02)(130)(310 - 278)

E = (0.02)(130)(32)

E = 83.2 J

3 0

3 years ago