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Artemon [7]
3 years ago
6

The compound 3-methylpentane is an example of

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

A) An Alkaline

Explanation:

An alkane that is pentane which is substituted by a methyl group at position 3. It is used as a solvent in organic synthesis, as a lubricant and as a raw material for producing carbon black.

You might be interested in
The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.320 M NaOH. What is the init
yan [13]

This question is incomplete, the complete question is;

The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator.

The buret contains 0.320 M NaOH,

It requires 11.2 mL of the NaOH solution to reach the end point of the titration

What is the initial concentration of HCI?

Answer:  

initial concentration of HCl is 0.3584 M

Explanation:

Given that;

the reaction between HCl and NaOH is 1:1 molar

HCl(aq) + NaOH(aq) -------> NaCl(aq) + H2O(l)

we know that molarity is the number of moles of solute per liter of solution

so moles of NaOH consumed

= ( 0.320 mol / 1000ml) × 11.2ml

= 0.003584 mol

now

0.003584 moles of NaOH reacts with 0.003584 moles of HCl

moles of HCl present in the 10.0ml solution = 0.003584 mol

therefore the initial concentration of HCl

= ( 0.003584 mol / 10.0ml )× 1000ml

= 0.3584 M

the initial concentration of HCl is 0.3584 M

5 0
3 years ago
What are the major problems associated with the production of nuclear energy?
Sindrei [870]

Answer:

• long time lag between planning and operation.

• cost.

• weapons proliferation risk.

• meltdown risk.

• mining lung cancer risk.

• carbon-equivalent emissions and air pollution.

• waste risk.

Explanation:

hope this help <33

7 0
3 years ago
The maximum energy of photo electrons (increases or decreases or remains constant) with increasing frequency and (increases or d
morpeh [17]

Answer:

Increases,  remain constant

Explanation:

In the light spectrum, the photons with a higher frequency (hence smaller wavelengths) have higher energy. The lower the energy the lower the frequency and longer the wavelengths. The intensity of light does not change the energy levels of these photons. The higher the intensity the higher the density of the photoelectrons.

4 0
3 years ago
Add oxidation numbers to the following reaction: 2 H3PO4 (aq) + 2 Cr(s) → 2 CrPO4 (aq) + 3 H2(g). Identify the atom that is oxid
rewona [7]

The atom that is oxidized : Cr

The oxidizing agent : H₃PO₄

<h3>Further explanation</h3>

Reaction

2 H₃PO₄ (aq) + 2Cr(s) → 2 CrPO₄ (aq) + 3H₂(g)

Atoms undergoing a reduction reaction (decrease in oxidation number) and an oxidation reaction (increase in oxidation number)

  • Reduction (+1 to 0)

H⁺(in H₃PO₄) =+1

H₂=0

  • Oxidation (0 to +3)

Cr = 0

Cr³⁺(in CrPO₄ )

the oxidizing agent.⇒which undergoes a reduction reaction and oxidizes another compound/element : H₃PO₄

3 0
3 years ago
WILL MARK BRAINLIEST PLZ HELPP
Mashutka [201]

Answer:

The answer to your question is below

Explanation:

I just write the formulas of the reactants and products and balanced the reactions.

a)

          3H₂(g)  +  N₂(g)   ⇒   2NH₃

b)

          2K  +  2H₂O  ⇒   2KOH  +  H₂ (g)

c)

         2Al(s)   +  Fe₂O₃  ⇒   Al₂O₃  +  2Fe

d)

         Fe₂O₃  +  2Al   ⇒  Al₂O₃  +  2Fe

e)

         Ba(OH)₂  +  2HBr   ⇒   BaBr₂  +  2H₂O

f)

         CaCO₃  + Δ ⇒  CaO  + CO₂

3 0
3 years ago
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