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4 years ago

find the length of nichrome wire of resistivity 100*10-6ohm-m of cross section 1mm ²to yield a resistance of 10 ohm

Physics

1 answer:

Burka [1]4 years ago

8 0

1 x 10⁻¹¹m²

Explanation:

Given parameters:

Resistivity = 100 x 10⁻⁶Ohm.m

Cross-section = 1mm²

Resistance = 10ohm

Unknown:

length of the nichrome wire = ?

Solution:

To find the length of the nichrome wire, we use the expression below:

L = $\frac{RA}{P}$

where l is the length of the wire

R is the resistance of the wire

A is the area

p is the resistivity

Now we need to convert area from mm to m;

1000mm = 1 m

1mm² = 1 x $\frac{1m}{1000mm} x \frac{1m}{1000mm}$ = 1 x 10⁻⁶m²

Input the values in the formula;

L = $\frac{100 x 10^{-6} x 1 x 10^{-6} }{10}$ = 1 x 10⁻¹¹m²

learn more:

Resistivity brainly.com/question/12246020

#learnwithBrainly

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A cement block accidentally falls from rest from the ledge of a 52.9-m-high building. When the block is 14.3 m above the ground,

Anna007 [38]

Answer:

The man has at most 0.418 secs to get out of the way

Explanation:

To determine how much time at most the man has to get out of the way, we will calculate the time it will take the block to reach height 1.94m from height 14.3m.

To do this, we will first determine the time it will take the block to reach height 1.94 m from height 52.9 m and find the time it takes the block to reach height 14.3m above the ground from the same height (52.9 m), the difference is the time the man has to get out of the way.

Now, the time it will take the block to reach height 1.94 m from height 52.9 m

This means the time it will take the block to travel a height distance of 52.9m - 1.94m = 50.96m

From one of the equations of motions for free falling bodies

h = ut + 1/2(gt²)

Where h is the height

u is the initial velocity

t is the time

and g is the acceleration due to gravity (Take g = 9.8 m/s²)

From the question, the block falls from rest

∴ u = 0 m/s

h = 50.96 m

Putting these into the equation

50.96 = 0(t) + 1/2(9.8)(t²)

50.96 = 4.9t²

t² = 50.96/4.9

t² = 10.4

t = √10.4

t = 3.225 secs

This is the time it will take to reach height 1.94m (that is to reach the man)

For the time it takes the block to reach height 14.3m above the ground from height 52.9 m

That is, the time it takes the block to travel a height distance of 52.9m - 14.3m = 38.6 m

Here,

h = 38.6 m

and u = 0 m/s

Putting these into the same equation

h = ut + 1/2(gt²)

38.6 = 0(t) + 1/2(9.8)(t²)

38.6 = 4.9t²

t² = 38.6/4.9

t² = 7.878

t = √7.878

t = 2.807 secs

This is the time it takes the block to reach height 14.3 m

Now, the difference in time is 3.225secs - 2.807 secs = 0.418 secs

Hence, the man has at most 0.418 secs to get out of the way.

7 0

3 years ago

At a country music festival, a band is playing at the end of a crowded

Anna11 [10]

Answer:

t=4.86s

Explanation:

To find the wavelength you use the following formula:

$v=\lambda f$

v: speed of sound = 343m/s

f: frequency = 400Hz

λ: wavelength of the sound

By doing λ the subject of the formula and replacing the values of f and v you obtain:

$\lambda=\frac{v}{f}=\frac{343m/s}{400Hz}=0.85m$

Now, to calculate the time that sound takes to reach the last row you use:

$t=\frac{d}{v}$

t: time

d: distance to the last row = 1947m

$t=\frac{1947m}{400Hz}=4.86s$

hence, the time is 4.86s

4 0

4 years ago

Find τf, the torque about point p due to the force applied by the achilles' tendon.

Luba_88 [7]

The formula for the torque is
τf = p F
where
τf is the torque
p is the distance where the force is applied by the tendon
F is force applied by the tendon

If there are given values, substitute in the equation and solve for the torque.

3 0

4 years ago

There is more than one answer

Sveta_85 [38]

Explanation:

the answers are the first 3.

5 0

3 years ago

Read 2 more answers

Two objects that are not initially in thermal equilibrium are placed in close contact. After a while, the temperature of the cod

Dima020 [189]

Answer:

If the temperature of the colder object rises by the same amount as the temperature of the hotter object drops, then the specific heats of both objects will be equal.

Explanation:

If the temperature of the colder object rises by the same amount as the temperature of the hotter object drops when the two objects of same mass are brought into contact, then their specific heat capacity is equal.

We can prove this by the equation of heat for the two bodies:

According to given condition,

$\Delta T_1=\Delta T_2$

$\frac{Q_1}{m_1.c_1} = \frac{Q_2}{m_2.c_2}$

when there is no heat loss from the system of two bodies then $Q_1=Q_2$

$\frac{1}{m.c_1} =\frac{1}{m.c_2}$

$\Rightarrow c_1=c_2$

Thermal conductivity is ultimately affects the rate of heat transfer, however the bodies will attain their final temperature based upon their mass and their specific heat capacities.

The temperature of the colder object will rise twice as much as the temperature of the hotter object only in two cases:

when the specific heat of the colder object is half the specific heat of the hotter object while mass is equal for both.

the mass of colder object is half the mass of the hotter object while their specific heat is same.

3 0

3 years ago

find the length of nichrome wire of resistivity 100*10-6ohm-m of cross section 1mm ²to yield a resistance of 10 ohm​

find the length of nichrome wire of resistivity 100*10-6ohm-m of cross section 1mm ²to yield a resistance of 10 ohm