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4 years ago

6

Two tuning forks are played at the same time. One has a frequency of 176 Hz and the other is 178 Hz. How many beats per second a

re heard?

1 answer:

Anna [14]4 years ago

6 0

Answer:

There is 2 beats per second.

Explanation:

You have to subtract them to find your answer and 178 - 176= 2

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How to tell if vector is unit vector

Aliun [14]

You can tell if vector is an unit because it has something to do with taking the magnitude of the vector.
also has a length 1. thus you should use pythagoras to check.

Hope this help

7 0

4 years ago

What kind of image is formed when an object is placed at the focal point of a convex lens? Explain WHY this is the image that oc

mariarad [96]

Answer:

Since light does not actually pass through this point, the image is referred to as a virtual image. Observe that when the object in located in front of the focal point of the converging lens, its image is an upright and enlarged image that is located on the object's side of the lens.

Explanation:

4 0

3 years ago

Calculate the change in internal energy (ΔE) for a system that is giving off 25.0 kJ of heat and is changing from 12.00 L to 6.0

Alexxandr [17]

Explanation:

The given data is as follows.

q = -25.0 kJ, Pressure (P) = 1.50 atm

$\Delta V$ = (12 - 6) L = 6 L

Therefore, product of pressure and change in volume will be as follows.

$P \Delta V = 1.50 atm \times 6 L$

= 7.5 L atm

= $7.5 \times 101.3$

= 759.75 J

Now, we will calculate the change in internal energy as follows.

$\Delta E = q + w$

= $q + P \Delta V$

= -25000 kJ + 759.75 J

= 24240.25 J

or, = 24.240 kJ (as 1 kJ = 1000 J)

Thus, we can conclude that the change in internal energy ( $\Delta E$ ) for a system is 24.240 kJ.

7 0

4 years ago

Two balls are dropped from rest and allowed to fall. If one ball is allowed to fall for 1 s and the other for 3 s compare the di

kirill115 [55]

The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

time of fall of the first ball, t = 1 s
time of fall of the second ball, t = 3 s

The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

$h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m$

The distance traveled by the second ball is calculated as follows;

$h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m$

Thus, the second ball traveled a greater distance because it spent more time in motion.

Learn more here:brainly.com/question/5868480

3 0

2 years ago

Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19

aleksandr82 [10.1K]

Answer:

The answer to your question is distance between these electrons

= 1.386 x 10⁻¹⁴ m

Explanation:

Data

Force = F = 1.2 N

distance = d = ?

charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C

K = 8.987 x 10⁹ Nm²/C²

Formula

-To solve this problem use the Coulomb's equation

F = kq₁q₂ / r²

-Solve for r²

r² = kq₁q₂ / F

-Substitution

r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2

- Simplification

r² = 2.306 x 10⁻²⁸ / 1.2

r² = 1.922 x 10⁻²⁸

-Result

r = 1.386 x 10⁻¹⁴ m

7 0

4 years ago