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yulyashka [42]
3 years ago
15

Determine the COP. for this thermodynamic refrigerator

Physics
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

Explanation:

The efficiency of a refrigerator is defined in the terms of coefficient of performance (COP).

The ratio of amount of heat in cold reservoir to the work done is termed as the COP.

COP = QL / W

COP = T2 / (T1 - T2)

Where, T1 be the temperature of hot reservoir, T2 be the temperature of cold reservoir.

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A square wire, 20 cm on the side, moves at constant speed parallel to the xy-plane into a region where there is a uniform magnet
Amanda [17]

Answer:

The speed of the wire is 5 m/s.

Explanation:

Given that,

Length = 20 cm

Magnetic field = 0.1 T

Current = 10 mA

Resistance R= 10\Omega

We need to calculate the  speed of the wire

Using formula of emf

\epsilon=Bvl

Using formula of current

I=\dfrac{\epsilon}{R}

Put the value of \epsilon into the formula of current

I=\dfrac{Bvl}{R}

v=\dfrac{IR}{Bl}

v=\dfrac{10\times10^{-3}\times10}{0.1\times20\times10^{-2}}

v= 5\ m/s

Hence, The speed of the wire is 5 m/s.

6 0
3 years ago
What is a disadvantage of using moving water to produce electricity
klemol [59]
Most of the time the towns get flooded and many people die and lose their homes and their jobs, businesses by the floods and the natural environment is destroyed ,air pollution is produced, the ecosystem could be disrupted and dams are known to fall over and dams are really expensive to build, The dams also cause geological damage, example earthquakes and spills happen.
4 0
3 years ago
Simplify 6.25 − 8.<br><br>please help
tatyana61 [14]

6.25 - 8 = -1.75

Hope this helps

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7 0
3 years ago
A shopper does 157 J of work pushing a cart with 10.9 N force
Tanzania [10]

The cart travelled a distance of 14.4 m

Explanation:

The work done by a force when pushing an object is given by:

W=Fd cos \theta

where:

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this problem we have:

W = 157 J is the work done on the cart

F = 10.9 N is the magnitude of the force

\theta=0^{\circ}, assuming the force is applied parallel to the motion of the cart

Therefore we can solve for d to find the distance travelled by the cart:

d=\frac{W}{F cos \theta}=\frac{157}{(10.9)(cos 0)}=14.4 m

Learn more about work:

brainly.com/question/6763771  

brainly.com/question/6443626  

#LearnwithBrainly

4 0
3 years ago
A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of
lorasvet [3.4K]

Answer:

19.6 m/s

Explanation:

The parameters given are:

Mass M = 20 Kg

Force F = 285 N

Angle Ø = 30 degree

Time t = 4 seconds

Coefficient of friction = 0.72

At the plane, the weight of the box will be mgsinØ

Resolving forces at the plane, we will have:

MgsinØ + Fr = F

Where Fr = frictional force.

Fr = F - mgsinØ

Substitute all the parameters into the formula

Fr = 285 - 20 × 9.8 sin30

Fr = 285 - 98

Fr = 187 N

But for the box moving toward the top of the plane,

F - Fr = ma

Where a = V/t

Substitute all the parameters involved into the formula

285 - 187 = 20 ( V/4)

98 = 5V

V = 98/5

V = 19.6 m/s

Therefore, the speed with which the box is moving is 19.6 m/s

4 0
3 years ago
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