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3 years ago

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Reactions occur when 2 or more atoms or molecules combine to form a larger, more complex molecule. this can occur through the lo

ss if water and therefore can be called

1 answer:

Luden [163]3 years ago

7 0

Loss of water molecules is known as condensation

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Why do they call Cleveland "the mistake by the lake"?

algol13

Mostly because the lake smell really bad and the waters really dirty

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3 years ago

Hydrogen is prepared commercially by the reaction of methane and water vapor at elevated temperatures. CH₄(????) + H₂O(????) ⇌ 3

sammy [17]

Answer:

6.2846

Explanation:

Given that:-

Concentrations at equilibrium :-

$[CH_4]=0.126\ M$

$[H_2O]= 0.242\ M$

$[CO]= 0.126\ M$

$[H_2]= 1.15\ M$

The equilibrium reaction is:-

$CH_4+H_2O\rightleftharpoons 3H_2+CO$

The expression for equilibrium constant is:

$K_{c}=\frac {\left [ H_2 \right ]^3\left [ CO \right ]}{\left [ CH_4 \right ]\left [ H_2O \right ]}$

Applying the values as:-

$K_c=\frac{1.15^3\times 0.126}{0.126\times 0.242}=6.2846$

<u>The equilibrium constant for the reaction is:- 6.2846</u>

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3 years ago

Which form of opera was performed without elaborate costumes, scenery, or acting?

GuDViN [60]

I believe the answer would be Oratorio it was a concert piece not a musical theatre

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Moving water carrying away small

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Answer:

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2 years ago

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A compound is found to have 55.7% hafnium+and+44.3%+chlorine.+what+is+the+empirical+formula?

uranmaximum [27]

The empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

<h3>How to calculate empirical formula?</h3>

The empirical formula of a compound is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.

The empirical formula of the given compound can be calculated as follows:

Hafnium = 55.7% = 55.7g
Chlorine = 44.3% = 44.3g

First, we convert mass values to moles by dividing by the molar mass of each element

Hafnium = 55.7g ÷ 178.49g/mol = 0.312mol
Chlorine = 44.3g ÷ 35.5g/mol = 1.25mol

Next, we divide each mole value by the smallest

Hafnium = 0.312 ÷ 0.312 = 1
Chlorine = 1.25 ÷ 0.312 = 4

Therefore, the empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

Learn more about empirical formula at: brainly.com/question/14044066

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7 0

1 year ago