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3 years ago

The most reactive metals are located at the of the periodic table.

Physics

2 answers:

NeX [460]3 years ago

7 0

Answer:

the elements towards the bottom left corner

Colt1911 [192]3 years ago

4 0

Explanation:

Metals are the substances which tend to lose their valence electrons in order to attain stability.

For example, metals of group 1 are lithium, sodium, potassium, rubidium and cesium.

And, each of these elements have only 1 valence electron present. So, it is much easier to lose just one electron rather than losing 2 or 3 valence electrons.

Hence, alkali metals are the most reactive substances of the periodic table and they are present at extreme left side of periodic table.

Therefore, we can conclude that the most reactive metals are located at the extreme left of the periodic table.

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The valve in the exit pipe is closed . The density of water is 1000kg / m and the gravitational force on free fall of water is 1

Stels [109]

Answer:

300000

Explanation:

p=30x10x1000=30000pascal

7 0

2 years ago

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An observer stands on the side of the front of a stationary train. When the train starts moving with constant acceleration, the

Zarrin [17]

To solve this problem we will use the linear motion description kinematic equations. We will proceed to analyze the general case by which the analysis is taken for the second car and the tenth. So we have to:

$x = v_0 t \frac{1}{2} at^2$

Where,

x= Displacement

$v_0$ = Initial velocity

a = Acceleration

t = time

Since there is no initial velocity, the same equation can be transformed in terms of length and time as:

$L = \frac{1}{2} a t_1 ^2$

For the second cart

$2L \frac{1}{2} at_2^2$

When the tenth car is aligned the length will be 9 times the initial therefore:

$9L = \frac{1}{2} at_3^2$

When the tenth car has passed the length will be 10 times the initial therefore:

$10L = \frac{1}{2}at_4^2$

The difference in time taken from the second car to pass it is 5 seconds, therefore:

$t_2-t_1 = 5s$

From the first equation replacing it in the second one we will have that the relationship of the two times is equivalent to:

$\frac{1}{2} = (\frac{t_1}{t_2})^2$

$t_1 = \frac{t_2}{\sqrt{2}}$

From the relationship when the car has passed and the time difference we will have to:

$(t_2-\frac{t_2}{\sqrt{2}}) = 5$

$t_2 (\sqrt{2}-1) = 3\sqrt{2}$

$t_2= (\frac{5\sqrt{2}}{\sqrt{2}-1})^2$

Replacing the value found in the equation given for the second car equation we have to:

$\frac{L}{a} = \frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2$

Finally we will have the time when the cars are aligned is

$18 \frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2 = t_3^2$

$t_3 = 36.213s$

The time when you have passed it would be:

$20\frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2 = t_4^2$

$t_4 = 38.172$

The difference between the two times would be:

$t_4-t_3 = 38.172-36.213 \approx 2s$

Therefore the correct answer is C.

4 0

2 years ago

First to answer will be the brainliest I need the answer ASAP answer questions 2 3 and 4

Irina-Kira [14]

2. False

Explanation: When a wave's energy increases, the wave length/frequency decreases.

3. Bass Guitar

Explanation: It has the lowest frequency.

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7 0

3 years ago

Seatbelts are necessary to prevent your body from flying out of a vehicle during a crash. why does your body not stop with the c

Svetlanka [38]

Because you are separate from the car.

6 0

3 years ago

The angle between an incident<br>ray and the mirror is 40°.<br>1) What is the angle of reflection?

Vlad1618 [11]

Answer:

1) 50°

Explanation:

We need to find the angle of incidence first before finding the angle of reflection.

Angle of incidence = 90° - 40°

= 50°

Since the angle of incidence is the same as the angle of reflection, the angle of reflection here would be 50°.

5 0

3 years ago