Answer:
The power she can generate is 185.22 KW.
Explanation:
<h3><u>DATA</u></h3>
3.00m wide and 0.500m deep.
Cross sectional area = 1.500m^2
Velocity = 1.35m/s
Volumetric flow rate = Av = 18.00m^3/s
Mass flow rate = 18,000kg/s
Height = 4.20m
25.0% efficiency
<h3><u>
FORMULA:</u></h3>
P = dE / dt * eff
<h3><u>
SOLUTION:</u></h3>
18,000kg/s (9.8m/s^2) (4.20m) (25%) = 185,220 watts
= 185 kw
Answer:
1) F = 24 N
2) Distance = 1 m
Explanation:
We are given;
Mass; m = 120 g = 0.12 kg
Initial velocity; u = 20 m/s
Final velocity; v = 0 m/s since it came to rest.
Time; t = 0.1 s
We can calculate acceleration from Newton's first equation of motion;
a = (v - u)/t
a = (0 - 20)/0.1
a = -200 m/s²
1) magnitude of the resistance will be;
F = ma
F = 0.12 × (-200)
F = -24 N
Since, we are dealing with the magnitude, we will take the absolute value. Thus, F = 24 N
2) To find the distance moved by the bullet, we know that;
Distance = Average speed × time
Thus;
Distance = ((v + u)/2) × t
Distance = ((0 + 20)/2) × 0.1
Distance = 1 m
Answer:0.153 Hz
Explanation: The relation between Time Period(T) and frequency(f) is given by T=1/f
Plug in the values and u arrive at the answer
