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Delicious77 [7]
3 years ago
15

A boy is exerting a force of 70 N at a 50-degree angle on a lawnmower. He is accelerating at 1.8 m/s2. Round the answers to the

nearest whole number.
What is the mass of the lawnmower?
What is the normal force exerted on the lawnmower?
Physics
1 answer:
Marysya12 [62]3 years ago
5 0

The lawnmower accelerates in the positive horizontal direction, so that the net horizontal force is, by Newton's second law,

(70 N) cos(-50°) = <em>m</em> (1.8 m/s²)

where <em>m</em> is the mass of the lawnmower. Solve for <em>m</em> :

<em>m</em> = ((70 N) cos(-50°)) / (1.8 m/s²)

<em>m</em> ≈ 25 kg

The lawnmower presumably doesn't get lifted off the ground, so that the net vertical force is 0. If <em>n</em> is the magnitude of the normal force, then by Newton's second law,

<em>n</em> - <em>m g</em> + (70 N) sin(-50°) = 0

<em>n</em> = <em>m g</em> + (70 N) sin(50°)

<em>n</em> = (25 kg) (9.8 m/s²) + (70 N) sin(50°)

<em>n</em> ≈ 300 N

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