The answer is 2) 1.0c. Light will always propagate through a vacuum at the speed of light “c”; even when moving at a significant fraction of the speed of light, observers will still measure this as the speed of light and the difference is resultant of time dilation.
Answer:
, ![T_{2} \approx 23.324\,N](https://tex.z-dn.net/?f=T_%7B2%7D%20%5Capprox%2023.324%5C%2CN)
Explanation:
First we build the Free Body Diagram (please see first image for further details) associated with the mass, we notice that system consist of a three forces that form a right triangle (please see second image for further details): (i) The weight of the mass, (ii) two tensions.
The requested tension and angle can be found by the following trigonometrical and geometrical expressions:
(1)
(2)
Where:
- Weight of the mass, measured in newtons.
,
- Tensions from the mass, measured in newtons.
If we know that
and
, then the requested values are, respectively:
![\theta = \tan^{-1} \frac{20\,N}{12\,N}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Ctan%5E%7B-1%7D%20%5Cfrac%7B20%5C%2CN%7D%7B12%5C%2CN%7D)
![T_{2} = \sqrt{(20\,N)^{2}+(12\,N)^{2}}](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20%5Csqrt%7B%2820%5C%2CN%29%5E%7B2%7D%2B%2812%5C%2CN%29%5E%7B2%7D%7D)
![T_{2} \approx 23.324\,N](https://tex.z-dn.net/?f=T_%7B2%7D%20%5Capprox%2023.324%5C%2CN)
Answer:
Emitted power will be equal to ![7.85\times 10^{-5}watt](https://tex.z-dn.net/?f=7.85%5Ctimes%2010%5E%7B-5%7Dwatt)
Explanation:
It is given factory whistle can be heard up to a distance of R=2.5 km = 2500 m
Threshold of human hearing ![I=10^{-12}W/m^2](https://tex.z-dn.net/?f=I%3D10%5E%7B-12%7DW%2Fm%5E2)
We have to find the emitted power
Emitted power is equal to ![P=I\times A](https://tex.z-dn.net/?f=P%3DI%5Ctimes%20A)
![P=I\times 4\pi R^2](https://tex.z-dn.net/?f=P%3DI%5Ctimes%204%5Cpi%20R%5E2)
![P=10^{-12}\times 4\times 3.14\times 2500^2=7.85\times 10^{-5}watt](https://tex.z-dn.net/?f=P%3D10%5E%7B-12%7D%5Ctimes%204%5Ctimes%203.14%5Ctimes%20%202500%5E2%3D7.85%5Ctimes%2010%5E%7B-5%7Dwatt)
So emitted power will be equal to ![7.85\times 10^{-5}watt](https://tex.z-dn.net/?f=7.85%5Ctimes%2010%5E%7B-5%7Dwatt)
You have to convert 400 cm into meters.
I'm assuming you mean a force of 10 Newtons in 8 seconds.
P= w/t
w=Fd
w= 10 x 4 = 40
P= 40 / 8 = 5
5 is your answer.
wind (b), also some others are:
- steam
- gas
- liquid fules