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devlian [24]
3 years ago
8

Any person who opens the door he applies​

Physics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

any person who opens the door he applies pulling force

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50200 J of heat are removed from
Dmitry_Shevchenko [17]

Correct Answer:

3.1375

Explanation:

Use equation Q=mcΔT to find m

Plug in all variables -50200=x\cdot 2000\cdot -8

Answer: 3.1375

4 0
4 years ago
What type of motion occurs when an object spins around an axis without altering its linear position?
dimulka [17.4K]
That would be only rotational motion
5 0
3 years ago
Where do we use friction in day to day life​
laila [671]

Answer:

walking in ground

while playing carrom

7 0
3 years ago
Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
Troyanec [42]

Answer:

The lowest possible frequency of sound is 971.4 Hz.

Explanation:

Given that,

Distance between  loudspeakers = 2.00 m

Height = 5.50 m

Sound speed = 340 m/s

We need to calculate the distance

Using Pythagorean theorem

AC^2=AB^2+BC^2

AC^2=2.00^2+5.50^2

AC=\sqrt{(2.00^2+5.50^2)}

AC=5.85\ m

We need to calculate the path difference

Using formula of path difference

\Delta x=AC-BC

Put the value into the formula

\Delta x=5.85-5.50

\Delta x=0.35\ m

We need to calculate the lowest possible frequency of sound

Using formula of frequency

f=\dfrac{nv}{\Delta x}

Put the value into the formula

f=\dfrac{1\times340}{0.35}

f=971.4\ Hz

Hence, The lowest possible frequency of sound is 971.4 Hz.

8 0
3 years ago
Snail 3, trying to keep up with Snail 2, managed to get to
Kipish [7]

Answer:

Acceleration is the change in velocity over the change in time = Δv/Δt.  To do these problems, you need to find out how much the speed changed and over what period of time it changed.

Snail 1 changes from 4 cm/min to 7 cm/min in 3 minutes.  Subtract the starting velocity (4 cm/min) from the ending velocity (7 cm/min) then divide by the time (3 min):

Snail 1 = (7 cm/min. - 4 cm/min)/(3 minutes) = ?    (remember to put down the units)

Snail 2 changed from 7 cm/min. down to 1 cm/min. in 3 minutes

Snail 2 = (1 cm/min. - 7 cm/min.)/(3 min.) = ?        (note that the acceleration is negative when you slow down)

I hope this helps you

6 0
3 years ago
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