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blagie [28]
3 years ago
13

What do you know about a chemical compound by looking at its chemical formula?

Chemistry
2 answers:
defon3 years ago
8 0
B. 
"The number and kinds of atoms in the compound." 

coldgirl [10]3 years ago
4 0
The type of bonds present in the compound. and the type of structure it has and the elements that are presents and the number of moles of each element in one mole of the compound.
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An atom of zinc that contains 30 protons and 38 neutrons would be named what
julia-pushkina [17]

Answer:

Explanation:

30+38

so this is the isosotope of Zn  that weighs 68

-so Zn68

6 0
3 years ago
What is the basic (smallest) unit of matter
seropon [69]

Answer:

atom

Explanation:

7 0
3 years ago
You have a hard glass flask that you plug up with a stopper at room temperature (25 C) and an internal pressure of 1 atm. If you
liubo4ka [24]

Answer:

pressure of 0atm

Explanation:

5 0
4 years ago
Calculate the molar mass of RbOH
Ghella [55]

Hey there!

RbOH

Rb: 1 x 85.468 = 85.468

O:  1 x 16 = 16

H: 1 x 1.008 = 1.008

------------------------------------

                   102.476

The molar mass of RbOH is 102.476 g/mol.

Hope this helps!

5 0
3 years ago
How to draw Hess' Cycle for this question ?
NISA [10]

Answer : The standard enthalpy of formation of ethylene is, 51.8 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of C_2H_4 will be,

2C(s)+2H_2(g)\rightarrow C_2H_4(g)    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)     \Delta H_1=-1411kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.7kJ/mole

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_3=-285.9kJ/mole

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equations, we get :

(1) 2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)     \Delta H_1=+1411kJ/mole

(2) 2C(s)+2O_2(g)\rightarrow 2CO_2(g)    \Delta H_2=2\times (-393.7kJ/mole)=-787.4kJ/mole

(3) 2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)    \Delta H_3=2\times (-285.9kJ/mole)=-571.8kJ/mole

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+1411kJ/mole)+(-787.4kJ/mole)+(-571.8kJ/mole)

\Delta H=51.8kJ/mole

Therefore, the standard enthalpy of formation of ethylene is, 51.8 kJ/mole

7 0
3 years ago
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