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3 years ago

7

The primary gas in a volocano is?

2 answers:

Dominik [7]3 years ago

6 0

Answer:

<h2>By far the most abundant volcanic gas is water vapor, which is harmless. However, significant amounts of carbon dioxide, sulfur dioxide, hydrogen sulfide and hydrogen halides can also be emitted from volcanoes.</h2>

Explanation:

stiv31 [10]3 years ago

4 0

Answer:

By far the most abundant volcanic gas is water vapor, which is harmless. However, significant amounts of carbon dioxide, sulfur dioxide, hydrogen sulfide and hydrogen halides can also be emitted from volcanoes

Explanation:

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3 years ago

Which statement is true of a reversible reaction at equilibrium?

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Answer:

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The concentration of reactants and the concentration of products are constant.

Explanation:

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3 years ago

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Change the coefficients until the reaction is balanced. (also if anyone could help me find the rest of the gizmos I would be ver

Artemon [7]

Answer:

1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O

Explanation:

1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 1NaC₂H₃O₂

1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂

(on the reactant side there are two molecules of C₂H₃O₂ and 2 atoms of Na, so in order to balance that we put the coefficient 2 on NAC₂H₃O₂)

So the final product is

1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂

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3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

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3 years ago

A sample of 0.0255 mol potassium hydroxide, KOH, was dissolved in water to yield

Mariana [72]

The answer i got was 2.55 M KOH

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3 years ago