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2 years ago

If 23.5 g of magnesium occupies 13.5 cm^3 what is the density of magnesium

Chemistry

1 answer:

lara31 [8.8K]2 years ago

4 0

The density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³

<h3>What is Density ?</h3>

Density is the measurement of how tightly a material is packed together.

It is defined as the mass per unit volume.

Given ;

Mass = 23.5 g
Volume = 13.5 cm³

Formula to calculate density ;

Density = mass / volume

=23.5 / 13.5 = 1.74 g/cm³

Hence, the density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³.

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Petunia needs 66.48 grams of potassium hydroxide (KOH) to run a reaction in class. How many moles of potassium hydroxide does sh

Kaylis [27]

Answer:

She needs 1.19 moles of potassium hydroxide.

Explanation:

Being the molar mass of the elements:

K= 39 g/mole
O= 16 g/mole
H= 1 g/mole

then the molar mass of potassium hydroxide is:

KOH= 39 g/mole + 16 g/mole + 1 g/mole= 56 g/mole

Being the mass of one mole of a substance, which can be an element or a compound, you can apply the following rule of three: if 56 g of KOH are present in 1 mole, 66.48 g of KOH in how many moles of the compound are they?

$moles of KOH=\frac{66.48 grams*1 mole}{56 grams}$

moles of KOH= 1.19

<u><em> She needs 1.19 moles of potassium hydroxide.</em></u>

4 0

3 years ago

A bicycle pump contains 250 mL of air at a pressure of 102 kPa. If the pump is

CaHeK987 [17]

Considering the Boyle's law, the new volume becomes 1,148,344.444 mL or 1148.34 L.

<h3>Boyle's law</h3>

Boyle's law relates pressure and volume, stating that the volume occupied by a given mass of gas at constant temperature is inversely proportional to pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following is true:

P1×V1=P2×V2

<h3>New volume</h3>

In this case, you know:

P1= 102 kPa= 10335.1 atm (being 1 kPa= 101.325 atm)
V1= 250 mL
P2= 2.25 atm
V2= ?

Replacing in the Boyle's law:

10335.1 atm ×250 mL= 2.25 atm×V2

Solving:

(10335.1 atm ×250 mL)÷ 2.25 atm= V2

Finally, the new volume becomes 1,148,344.444 mL or 1148.34 L.

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2 years ago

What is the law of redox reactions?

lbvjy [14]

Answer:

. All redox reactions occur with a simultaneous change in the oxidation numbers of some atoms. At least two elements must change their oxidation numbers. When an oxidation number of an atom is increased in the course of a redox reaction, that atom is being oxidized

Explanation:

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4 years ago

Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show the for

Alexus [3.1K]

Answer:

See explanation below

Explanation:

In this case, let's see both molecules per separate:

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Se = x

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x + (-2)*2 = 0

x - 4 = 0

x = +4.

Therefore, Selenium is working with +4 state, the only way to bond this molecule is with a covalent bond, and in the case of the oxygen will be with double bond. See picture below.

In the case of CO₂ happens something similar. Carbon is working with +4 state, so in order to stabilize the charges, it has to be bonded with double bonds with both oxygens. The picture below shows.

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4 years ago

What happens to the velocity when you apply a constant force to an<br> object? *

Degger [83]

Answer: it is part of newtons second law. so the object to your question would accelerate

Explanation: newtons second law

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4 years ago