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sineoko [7]
1 year ago
9

If 23.5 g of magnesium occupies 13.5 cm^3 what is the density of magnesium

Chemistry
1 answer:
lara31 [8.8K]1 year ago
4 0

The density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³

<h3>What is Density ?</h3>

Density is the measurement of how tightly a material is packed together.

It is defined as the mass per unit volume.

Given ;

  • Mass = 23.5 g
  • Volume = 13.5 cm³

Formula to calculate density ;

Density = mass / volume

             =23.5 / 13.5 = 1.74 g/cm³

Hence, the density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³.

Learn more about density here ;

brainly.com/question/15164682

#SPJ1

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Ulfur dioxide gas can react in the presence of oxygen and vanadium(V) oxide to form sulfur trioxide. Sulfur trioxide is the only
LenaWriter [7]

According to the illustration, the vanadium (V) oxide would be a catalyst.

<h3>What are catalysts?</h3>

Catalysts are substances that are utilized in reactions that are not themselves consumed in reactions but only speed up the rate of the reactions.

Catalysts speed up the rate of reactions by lowering the activation energy of the reactants.

Sulfur dioxide reacts with oxygen to produce sulfur trioxide. The vanadium (v) oxide is not consumed in the reaction. Thus it only serves as a catalyst.

More on catalysts can be found here: brainly.com/question/12260131

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2 years ago
Organisms can either be made of one cell or made of more than one cell
Alika [10]

Answer:

The statement is true.

Explanation:

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I hope this helps in any way :)

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3 years ago
Why is oiling done time and again in a sewing machine​
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8 0
3 years ago
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How many grams of carbon dioxide are produced from the combustion of 250.G of ethane, C3H8 in the reaction C3H8 +5O2 - 3CO2 +4H2
ludmilkaskok [199]

Answer:

750 g of CO₂

Explanation:

The balanced equation for the reaction is given below:

C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O

Next, we shall determine the mass of C₃H₈ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C₃H₈ = (12×3) + (8×1)

= 36 + 8 = 44 g/mol

Mass of C₃H₈ from the balanced equation = 1 × 44 = 44 g

Molar mass of CO₂ = 12 + (16×2)

= 12 + 32 = 44 g/mol

Mass of CO₂ = 3 × 44 = 132 g

SUMMARY:

From the balanced equation above,

44 g of C₃H₈ reacted to produce 132 g of CO₂.

Finally, we shall determine the mass of CO₂ produced by the reaction of 250 g of C₃H₈. This can be obtained as follow:

From the balanced equation above,

44 g of C₃H₈ reacted to produce 132 g of CO₂.

Therefore, 250 g of C₃H₈ will react to produce = (250 × 132)/44 = 750 g of CO₂.

Thus, 750 g of CO₂ were obtained from the reaction.

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