There is a missing portion of this question which shows the reaction that needs balancing:
"In a balanced equation, the same number of each kind of atom is shown on each side of the equation. Calculate the number of iron (Fe), oxygen (O), and carbon atoms (C).
Fe2O3+ 3CO --> 2Fe + 3CO<span>2
</span><span>Based on these values, is the equation balanced?</span><span>"
</span>
To check if this equation is balanced we simply compare the number of each element on each side of the equation.
On the reactant side of the equation we have:
2 Fe atoms
6 O atoms
3 C atoms
On the product side of the equation we have:
2 Fe atoms
6 O atoms
3 C atoms
Therefore, both side of the reaction have the correct and equal number of each atom, so the equation is balanced.
+1
Explanation:
To solve this problem, we need to set up an algebraic equation. Let us first understand the meaning of oxidation number.
The oxidation number is the formal charge assigned to an atom present in a molecule or formula unit
The algebraic sum of all oxidation numbers of atoms in an ion containing more than one kind of atom is the charge on the ion.
The algebraic sum of all oxidation number of atoms in a neutral compound is zero;
The radical NO₃ has a formal charge of -1;
let the oxidation number of Li = x
x + (-1) = 0
x = + 1
learn more:
Oxidation number brainly.com/question/10017129
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Slavery played a big role in this. the confederacy allowed slavery while the union was oppose to it.
212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.
Answer:
Option A.
Explanation:
Similar to Avagadro's law, there is another law termed as dilution law. As the product of volume and normality of the reactant is equal to the product of volume and normality of the product from the Avagadro's law. In dilution law, it will be as product of volume and concentration of the solute of the reactant is equal to the product of volume and concentration of solution.
So, as per the given question C1 = 5.45 M of lead nitrate and V1 has to be found. While C2 is 1.41 M of lead nitrate and V2 is 820.7 ml.
Then, 
So nearly 212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.
Answer:
1088.89 Pa
Explanation:
According to the Newton's second law of motion:-
Mass = 50.0 kg
Acceleration = g = 9.81 m/s²
So,
Force = 490 N
Area of the base = 
= 
m² = 0.45 m²
<u>Pressure = Force/Area = 
= 1088.89 Pa</u>
