Reaction of option c produces precipitate.
Rhodium on reacting with potassium phosphate produces rhodium phosphate which remain in solution due to low lattice energy for rhodium phosphate.
Niobium on reacting with lithium carbonate produces niobium carbonate and it will remain in aqueous form.
Cobalt on reacting with zinc nitrate produces cobalt nitrate. This, Co(NO3 )2 is insoluble precipitate and settles at bottom whereas zinc ion will remain in solution as follows:
Potassium ion on reacting with sodium sulfide produces potassium sulfide which remain in solution
The equation presented above is that of uranium reacting with fluorine forming uranium fluoride.
The chemical reaction can be balanced by carefully studying the equation and balancing the number of atoms of each of the element in both sides of the chemical reaction. That is,
<em> U(s) + 3F₂(g) --> UF₆(g)</em>
Answer:
6
Explanation:
if there is 10n and the friction is 4n on the table then it is 6n.
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Answer:
C
Explanation:
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The number of micrograms of contaminant each person will receive is 5,742.64 ug.
<h3>
Number of micrograms of contaminant per person</h3>
The number of micrograms of contaminant each person will receive is calculated as follows;
Amount of contaminant (mg) = (1.01 x 10⁻⁴ mg/mL) x 2.28 x 10⁴ L
Amount of contaminant (mg) = 2.3028 mg.L/mL
Amount of contaminant (mg) = (2.3028 mg.L/mL) x (1000 mL/L) = 2,302.8 mg
Amount of contaminant (ug) = 2,302.8 mg x 1000 ug/mg = 2,302,800 ug
<h3>Amount of contaminant per person (ug/person) </h3>
= (2,302,800 ug) / (401 persons)
= 5,742.64 ug per person
Learn more about micrograms of contaminant here: brainly.com/question/14522199
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