Molar mass=MM
MM(Hg)=200.59g/mol
MM(N)=14.01g/mol
MM(O)=16.00g/mol
MM(Hg(NO3)2)=MM(Hg)+2*MM(N)+6*MM(O)=200.59g+2*14.01g+6*16g=324.61g/mol
1.60mol Hg(NO3)2*(324.61g/mol)=519.376 g=519 g Hg(NO3)2
Answer:
The numbers of moles in 20.0g of NaOH:
n=
=
=
(moles)
I believe the answer is false.
Answer:
5.90, 11.8, 47.2
Explanation:
Let’s remove the parentheses and write the formula as MgCl₂O₈.
We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.
∴
![\text{Moles of Cl atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{2 mol Cl atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{11.8 mol Cl atoms}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20Cl%20atoms%7D%20%3D%20%5Ctext%7B5.90%20mol%20Mg%28ClO%7D_%7B4%7D%29_%7B2%7D%20%5Ctimes%20%5Cfrac%7B%5Ctext%7B2%20mol%20Cl%20atoms%7D%7D%20%7B%5Ctext%7B1%20mol%20Mg%28ClO%7D_%7B4%7D%29_%7B2%7D%7D%20%3D%20%5Ctext%7B11.8%20mol%20Cl%20atoms%7D)
![\text{Moles of O atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{8 mol O atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{47.2 mol O atoms}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20O%20atoms%7D%20%3D%20%5Ctext%7B5.90%20mol%20Mg%28ClO%7D_%7B4%7D%29_%7B2%7D%20%5Ctimes%20%5Cfrac%7B%5Ctext%7B8%20mol%20O%20atoms%7D%7D%20%7B%5Ctext%7B1%20mol%20Mg%28ClO%7D_%7B4%7D%29_%7B2%7D%7D%20%3D%20%5Ctext%7B47.2%20mol%20O%20atoms%7D)
∴ Mg, Cl, O = 5.90, 11.8, 47.2