<span>The molar volume of ammonia at standard temperature and pressure (STP) is 22.4L. This is the standard molar volume of any gas at these conditions.</span>
The answer would be B because you can go and find evidence and facts to conduct an investigation on that.
Answer:
the % yield is 82%
Explanation:
Given the data in the question,
we know that;
Molar mass of benzil is 210.23 g·mol−1
Molar mass of dibenzyl ketone is 210.27 g·mol−1
Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1
Now,
2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole
2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole
3.0 g of tetraphenylcyclopentadienone = 3 / 384.5 = 0.0078 mole
Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone
percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%
= 0.82 × 100%
= 82%
Therefore, the % yield is 82%
Answer:
Option 4
Explanation:
Hydrochloric acid is a strong one, that gives protons to medium. It can be dissociated as this:
HCl → H⁺ + Cl⁻
M means Molarity. It is a sort of concentration that indicates the moles of solute in 1L of solution.
M = moles / volume (L)
We can also say M = mmoles / mL of solution
M . mL = mmoles
0.453 M . 62.85mL = 28.5 mmoles
If we divide by 1000 → 28.5 mmol . 1 mol / 1000 mmol = 0.0285
