Answer:
You need Light for Chlorophyll activation
So I guess its The Light Absorbing Pigment.
Answer:
The fraction of heterozygous individuals in the population is 32/100 that equals 0.32 which is the genotipic proportion for these endividuals.
Explanation:
According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.
In the exposed example, the r-6 allelic frequency is 0,2. This means that if r-6=0.2, then the other allele frequency (R) is=0.8, and the sum of both the allelic frequencies equals one. This is:
p + q = 1
r-6 + R = 1
0.2 + 0.8 = 1
Then, the genotypic proportion for the homozygous individuals RR is 0.8 ² = 0.64
The genotypic proportion for the homozygous individuals r-6r-6 is 0.2² = 0.04
And the genotypic proportion for heterozygous individuals Rr-6 is 2xRxr-6 = 2 x 0.8 x 0.2 = 0.32
Hey there,
Paramecium feeds on micro-organisms such as bacteria, algae and yeasts.
Hope this helps :))
<em>~Top♥</em>
Answer:
C. Succinate is the substrate, and fumarate is the product.
Explanation:
Succinate is the substrate of the enzyme Succinate dehydrogenase, and as a product is obtained fumarate. In this scenario, malonic acid plays the role of a competitive inhibitor because its structure resembles the succinate's, so they compete for the active site of the enzyme. So, A option is wrong because fumarate is not the product. B option is wrong too because malonic acid is an inhibitor, not the substrate. Also, D is incorrect because malonic acid is a COMPETITIVE inhibitor, not a noncompetitive one. Finally, E can´t be true because malonic acid is not product and fumarate is the product, not an inhibitor.
