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Whitepunk [10]
3 years ago
10

To find a gene, you have to associate a phenotype with a genotype (e.g. all individuals with white flowers have a certain allele

). It is MUCH harder to find which genes are involved in polygenic traits than it is to find the genes responsible for discrete traits. Why?
Chemistry
1 answer:
Ugo [173]3 years ago
4 0
T's harder to find one of the many genes involved in a polygenic trait vs. the only gene involved in a discrete trait." 

<span>It is probably not very difficult to find ONE OF THE GENES involved in a polygenic trait (as this answer suggests), but it IS difficult to find ALL OF THE GENES involved in the trait. </span>

<span>This sounds like a high school Biology or first year university question - chances are they're testing your reading comprehension as much as your scientific knowledge.</span>
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Zepler [3.9K]
Mitochondria because is the power house for cell,site for respiration or energy release.
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Which of the following is correct concerning subatomic particles?
sveticcg [70]
The following answers:
1. B
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Cuales son los símbolos para representar que una reacción se produce en presencia de;
ycow [4]

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3 years ago
Copper has two naturally occurring isotopes, 63Cu (isotopic mass 62.9296 amu) and 65Cu (isotopic mass 64.9278 amu). If copper ha
Semenov [28]

Answer:

Percentage of first isotope = 69.152 %

Percentage of second isotope =  30.848 %

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

For first isotope:

Let % = x %

Mass = 62.9296 amu

For second isotope:

% = 100 - x  %  (Since, there are only two isotopes)

Mass = 64.9278 amu

Average mass = 63.546 amu

Thus,  

63.546=\frac {x}{100}\times {62.9296}+\frac {(100-x)}{100}\times {64.9278}

Solving,

1.9982 x = 138.18

Thus,

<u>Percentage of first isotope = x = 69.152 %</u>

<u>Percentage of second isotope = 100 - x % = 30.848 %</u>

5 0
4 years ago
What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
Vanyuwa [196]

Answer:

Mole fraction for solute = 0.1, or 10%

Molality = 6.24 mol/kg

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22.3% by mass → In 100 g of solution, we have  22.3 g of HCOOH

Mass of solution = 100 g

Mass of solute = 22.3 g

Mass of solvent = 100 g - 22.3g = 77.7 g

Let's convert the mass to moles

22.3 g . 1mol/ 46 g = 0.485 moles

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Xm for solute = 0.485 / 4.805 = 0.100 → 10%

Molality → mol/ kg → we convert the mass of solvent to kg

77.7 g.  1 kg / 1000g = 0.0777 kg

0.485 mol / 0.0777 kg = 6.24 m

6 0
3 years ago
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