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2 years ago

5

An ice tray full of ice became half full when it was left in the freezer for a long period of time. What phase change made this

occur? A. plasma B. heat C. sublimation D. melting

1 answer:

zysi [14]2 years ago

5 0

C. Sublimation, hope this helps

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S8 + 12 O2 → 8 SO3<br>How many moles of SO3 can be produced from 6 moles of O2?

MA_775_DIABLO [31]

Answer:

4 moles of SO3 will be produced from 6 moles of oxygen.

Explanation:

From the reaction given

S8 + 12 O2 ----> 8 SO3

12 moles of oxygen reacts to form 8 moles of SO3

if 6 moles of oxygen were to be used instead, it has been reduced to half of the original mole of oxygen used. Then the moles of SO3 will also be reduced to half.

6 moles of O2 will yield 4 moles of SO3

12 moles = 8 moles

6 moles = ?

? = 6 * 8 / 12

? = 48/ 12

? = 4 moles of SO3.

8 0

3 years ago

A _____ exists in the same physical state as that of the reaction it catalyzes.

klio [65]

<span>A Homogeneous Catalyst exists in the same physical state as that of the reaction it catalyzes.

Explanation:
Catalysts are classifies as follow,
1. Homogeneous Catalyst
2. Heterogeneous Catalyst

</span>Homogeneous Catalyst are those which are in same phase as that of reactants are.

Example:

Acetic Acid + Ethanol + H₂SO₄ → Ethyl Acetate + H₂O + H₂SO₄

In this reaction catalyst and reactants all are in same phase i.e. Liquids.

Heterogeneous Catalyst are those which are in different phase as that of reactants are.

Example:

Ethene + H₂ + Ni → Ethane + Ni

In this reaction ethene and hydrogen are gases while Nickle catalyst is in solid state.

6 0

2 years ago

When 15.3 g of sodium nitrate, NaNO3,was dissolved in water in a calorimeter, the temperature fell from 25.00oC to 21.56oC. If t

satela [25.4K]

Answer:

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

Explanation:

Heat lost by solution ad calorimeter = Q

Heat capacity of solution ad calorimeter = C = 1071 J/°C

Change in temperature = ΔT = 21.56°C - 25.00°C = -3.44°C

$Q=C\times Delta T$

$Q=1071 J/^oC\times (-3.44^oC)=-3,684.24 J$

Heat gained by sodium nitrate = -Q = -(-3,684.24 J)=3,684.24 J

Moles of sodium nitrate = $\frac{15.3 g}{85 g/mol}=0.18 mol$

When 0.18 mole of sodium nitrate was dissolved in water 3,684.24 joulesof heat was absorbed by it.

Then heat absorbed by 1 mole of sodium nitrate :

$\frac{3,684.24 J}{0.18}=20,468 J=20.468 kJ$

1 J = 0.001 kJ

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

8 0

2 years ago

More knowledge about de the topic of momenclature of organic compounds

vichka [17]

Answer:

The primary function of chemical nomenclature is to ensure that a spoken or written chemical name leaves no ambiguity concerning which chemical compound the name refers to: each chemical name should refer to a single sub

3 0

1 year ago

Balanced equation of potassium chloride and ammonium nitrate; it’s types, net and observation

ASHA 777 [7]

Potassium chloride reacts with ammonium nitrate to give ammonium chloride and potassium nitrate.

This is a type of double displacement reaction. The balanced chemical equation can be represented as,

$KCl(aq)+NH_{4}NO_{3}(aq)-->NH_{4}Cl(aq)+KNO_{3}(aq)$

Total ionic equation for this reaction will be,

$K^{+}(aq)+Cl^{-}(aq)+NH_{4}^{+}(aq)+NO_{3}^{-}(aq)--> K^{+}(aq)+NO_{3}^{-}(aq)+NH_{4}^{+}(aq)+Cl^{-}(aq)$

There is no apparent reaction as this reaction is not accompanied by the formation of a gas or a solid precipitate. We cannot observe any visual reaction as there is not net reaction taking place. All the ions remain as spectator ions.

5 0

3 years ago