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2 years ago

A truck traveling with an initial velocity of 22m/s comes to a stop in 17.32 secs. What is the acceleration of the truck?

Physics

2 answers:

Tomtit [17]2 years ago

6 0

Explanation:

Given:

v₀ = 22 m/s

v = 0 m/s

t = 17.32 s

Find: a

v = at + v₀

(0 m/s) = a (17.32 s) + (22 m/s)

a = -1.270 m/s²

Round as needed.

trasher [3.6K]2 years ago

6 0

<u>Answer:</u>

A truck traveling with an initial velocity of 22 m/s comes to a stop in 17.32 sec, the acceleration of the truck is $- 1.27 m/s^2$

<u>Explanation</u>

From the Given statements, we know that Initial Velocity (u) = 22 m/s

time (t) = 17.32 seconds

Final Velocity (v) = 0 m/s [ because the truck Stops]

find acceleration on Applying the Equation of Motion

v = u + at

substituting the values in above equation, we find

a = $\frac{\mathrm{v}-\mathrm{u}}{\mathrm{t}}$

= $\frac{0-22}{17.32} \mathrm{m} / \mathrm{s}^{2}$

a = $- 1.27 m/s^2$ [negative sign shows reverse direction]

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Answer:

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Explanation:

From the question we are told that

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Here $d\phi$ is the change in magnetic flux which is mathematically represented as

$d \phi = dB * A$

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substituting values

$dB = 2.60 - 0.500$

$dB = 2.1 \ T$

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$|\epsilon| = 1.69 *10^{-3} \ V$

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3 years ago

An object acted on by three forces moves with constant velocity. One force acting on the object is in the positive xx direction

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Answer with Explanation:

We are given that

$F_1=6.9 N$

$F_2=4.5 N$

We have to find the direction and magnitude of the third force acting on the object.

Resultant force,F= $\sqrt{F^2_1+F^2_2}$

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Angle lies in second quadrant because the direction of third force is opposite to the direction of the resultant force of F1 and F2.

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3 years ago

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3 years ago

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Answer:

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Given that,

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Putting all the values,

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