They begin to adapt into their new location. They then end up having adaptations to help them survive.
Explanation:
1-How many moles of NazCOs are in 10.0 ml of a 2.0 M solution?
2-How many moles of NaCl are contained in 100.0 ml of a 0.20 M solution?
3- What weight (in grams) of H2SO4 would be needed to make 750.0 ml of
2.00 M solution?
4-What volume (in ml) of 18.0 M H2SO4 is needed to contain 2.45 g H2S04?
You have to solve this by using the equations of motion:
u=3
v=0
s=2.5
a=?
v^2=u^2+2as
0=9+5s
Giving a=-1.8m/s^2
Then using the equation:
F=ma
F is the frictional force as there is no other force acting and its negative as its in the opposite direction to the direction of motion.
-F=25(-1.8)
F=45N
Then use the formula:
F=uR
Where u is the coefficient of friction, R is the normal force and F is the frictional force.
45=u(25g)
45=u(25*10)
Therefore, the coefficient of friction is 0.18
Hope that helps
Answer:
68kg
Explanation:
1 cm^3 is the same as 1 mL and there are 5000mL in 5L
Therefore if the density is 13.6g/mL we multiply 13.6 by 5000 to get the amount of grams required = 68000g which is 68kg